anonymous
  • anonymous
A quantity P obeys the exponential growth law P(t)=Ce^kt (t in years). Find the formula for P(t), assuming that the doubling time is 7 years & P(0)=100.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
P(0) = 100 means 100 = C*1, so C = 100
anonymous
  • anonymous
Would k = 7 because that's the doubling time ?
anonymous
  • anonymous
wouldn't it mean that e^(k*7) = 2? since after 7 years, you have multiplied by 2?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
then ln2 = k*7, and k = (ln2)/7 Does that make sense?
anonymous
  • anonymous
then when t = 14, e^((ln2/7)*14) = e^2ln2 = e^ln4 = 4 I think that's it. take your "doubling time and make it into a fraction of ln2/(doubling time) =k
anonymous
  • anonymous
I kind of get it, let me work it out on paper. Thanks!
anonymous
  • anonymous
hello again, the formula would be P(t) = 100e^(t*ln2/7)
anonymous
  • anonymous
Why wouldn't it be 4 ?
anonymous
  • anonymous
Oh , nevermind ! I got it . Thanks again !
anonymous
  • anonymous
no, the 4 was just to test it because I haven't done these in a while
anonymous
  • anonymous
Gotcha .

Looking for something else?

Not the answer you are looking for? Search for more explanations.