A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


  • 5 years ago

show the algebraic inequality. show work. Tammy has the following scores on her business law test 92,99,84,91. what score must she earn in order to an A average. and A at her univ starts at 90

  • This Question is Closed
  1. gw2011
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    (92+99+84+91+x)/5>=90 Where the symbol >= represents greater than or equal to and x represents the score needed 92+99+84+91+x>=(90)(5) 92+99+84+91+x>=450 Now add the numbers on the left side to get: 366+x>=450 x>=450-366 x>=84 Therefore, 84 is the lowest score needed in order to get an A average.

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.