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anonymous
 5 years ago
Simplify Completely. (9x^4y^2)^1/(y^3z^4) x (3y^1)^2/(xz^5)
anonymous
 5 years ago
Simplify Completely. (9x^4y^2)^1/(y^3z^4) x (3y^1)^2/(xz^5)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry this is a question dividing exponents and I thought I could use the ^ symbol to represent that, is that wrong? (9x^4y^2)^1/(y^3z^4) x (3y^1)^2/(xz^5) means 9x to the 4 power times y to the 2nd power divided by y to the 3 power times z to the 4th power, all in parentheses to the 1st power. then times that by 3y to the 1st power divided by xz to the 5th power in parentheses, all to the 2nd power

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that's not wrong, i meant 1/x equal to x^1 so, (9x^4y^2)^1 = 1/(9x^4y^2)
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