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anonymous
 5 years ago
simplify (x^3/5)^7/6. no clue where to begin on solving
anonymous
 5 years ago
simplify (x^3/5)^7/6. no clue where to begin on solving

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(a^x)^y = a^(xy) also, (m/n) *(p/q) = mp/nq

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so what numbers plug into where. I definetly missed this part in class

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no, you dont plug anything anywhere. I was just showing rules of how exponents and multiplying fractions work.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(x^3/5)^7/6 = x^(3/5)*(7/6) so since (3/5)*(7/6) = (21/30) = (7/10) the answer is x^(7/10)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the rules is " a raised to the power x raised to the power y is equal to a raised to the power product of x and y"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(x^3/5)^7/6 = x^(3/5)*(7/6) so since (3/5)*(7/6) = (21/30) = (7/10) the answer is x^(7/10)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so say if it was switched to (x^5/3)^9/4 it would be 45/12 = 15/4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes that would be correct x^(15/4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, grags, very good!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0to check this...plug a number into your calculator for x. lets say x=5, so (5^5/3)^9/4 = 417.9626906 now plug 5 into what you think is the correct answer of x^(15/4) 5^(15/4) also equals 417.9626906 so your answer checks

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok lets hope i remember that. Final is tomorrow and i am doing a final review. somehow after 40 hours this week of studying i still am getting hung up on some questions
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