anonymous
  • anonymous
simplify (x^3/5)^7/6. no clue where to begin on solving
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
(a^x)^y = a^(xy) also, (m/n) *(p/q) = mp/nq
anonymous
  • anonymous
so what numbers plug into where. I definetly missed this part in class
anonymous
  • anonymous
no, you dont plug anything anywhere. I was just showing rules of how exponents and multiplying fractions work.

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anonymous
  • anonymous
(x^3/5)^7/6 = x^(3/5)*(7/6) so since (3/5)*(7/6) = (21/30) = (7/10) the answer is x^(7/10)
anonymous
  • anonymous
the rules is " a raised to the power x raised to the power y is equal to a raised to the power product of x and y"
anonymous
  • anonymous
(x^3/5)^7/6 = x^(3/5)*(7/6) so since (3/5)*(7/6) = (21/30) = (7/10) the answer is x^(7/10)
anonymous
  • anonymous
so say if it was switched to (x^5/3)^9/4 it would be 45/12 = 15/4
anonymous
  • anonymous
yes that would be correct x^(15/4)
anonymous
  • anonymous
yes, grags, very good!
anonymous
  • anonymous
to check this...plug a number into your calculator for x. lets say x=5, so (5^5/3)^9/4 = 417.9626906 now plug 5 into what you think is the correct answer of x^(15/4) 5^(15/4) also equals 417.9626906 so your answer checks
anonymous
  • anonymous
ok lets hope i remember that. Final is tomorrow and i am doing a final review. somehow after 40 hours this week of studying i still am getting hung up on some questions

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