anonymous
  • anonymous
solve for t: 17e^(0.07t)=11e^(0.05t) I have so far gotten to this step: 17t ln(0.07)=tln(0.05)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
HELP ME PLEASE
anonymous
  • anonymous
divide by e^(0.05t) on both sides
anonymous
  • anonymous
and post what you get.

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anonymous
  • anonymous
ok hold on
anonymous
  • anonymous
17tln(0.07)-tln(0.05)=11
anonymous
  • anonymous
\[e ^{x} / e ^{y} = e ^{x-y}\]\[\ln{e^{x-y}} = x - y\]
anonymous
  • anonymous
how did you get to the step that you got to? what did you do to get 17t ln(0.07)=tln(0.05)? because that is incorrect.
anonymous
  • anonymous
I did this : 17e^(0.07t)/(e^(0.05t) = 11
anonymous
  • anonymous
ok, thar part is right. what did you do after that?
anonymous
  • anonymous
okay, and then?
anonymous
  • anonymous
is it possible that you can take a picture of your notes and attach it here? that way it is much faster.
anonymous
  • anonymous
according to the quotient rule u subtract?
anonymous
  • anonymous
right, you subtract
anonymous
  • anonymous
so what did you get?
anonymous
  • anonymous
17tln(0.07) - tln(0.05)=11
anonymous
  • anonymous
why did you do tln0.07-tlon0.05? what rule is that?
anonymous
  • anonymous
idk. can u show me the next step. plz
anonymous
  • anonymous
alright so 17e^0.07t = 11e^0.05t Step 1: divide both sides by e^0.05t ...so you have (17e^0.07t)/(e^0.05t) = 11 Step 2: since e^x/y = e^x-y ...you can make this 17e^(0.07t-0.05t) =11 ...which equals???? 17e^0.02t = 11 Step 3: divide 17 out of there ...so e^0.02t = (11/17) step 4: take the natural log of both sides ...so ln e^0.02t = ln (11/17) step 5: e goes away now and you have 0.02t = ln (11/17) step 6: divide both sides by 0.02 so now it is t = (ln (11/17)/(0.02)) SO NOW..... t = -21.76590356 Check to see if this works in the original equation
anonymous
  • anonymous
hold on let me work it out
anonymous
  • anonymous
yup it works. i understand now, i was not certain at first if u can use the e^x/y rule
anonymous
  • anonymous
i understand the simplification
anonymous
  • anonymous
i messed up in my steps by going too fast and said e^x/y = e^x-y i meant to say (e^x) / (e^y) = e^x-y but i think you already figured that out
anonymous
  • anonymous
the rule is e^x/e^y = e^(x-y), not e^x/y = e^(x-y)
anonymous
  • anonymous
yep...caught myself there :)
anonymous
  • anonymous
yup. qoptient rules for natural logs right?
anonymous
  • anonymous
lol. no its the quotient rule for ALL fractions.
anonymous
  • anonymous
yep....now if you'll excuse me, i have to go make some natural logs of my own....;o
anonymous
  • anonymous
TMI
anonymous
  • anonymous
hahaha
anonymous
  • anonymous
suprisingly im an engineering major
anonymous
  • anonymous
lol
anonymous
  • anonymous
surprisingly, i earned a bachelor's in biochemistry....when i wasnt drunk...

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