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anonymous
 5 years ago
how do you solve this:
2x3 = (3+x)/2
anonymous
 5 years ago
how do you solve this: 2x3 = (3+x)/2

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0multiply by 2, subtract an x and add a 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i need the process, not the answer which i already know

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The point is, you want to get all your x terms on one side and your nonvariable terms on the other

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[2*(2x3)=[(3+x)/2]*2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then it goes to : 4x6=3+x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you so much, i understand now

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the get x by itself...so subtract x to the left so next step: 3x=9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes! but i don't know how to give one

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i need help with this one too please: 2x1= 1/3(53x) + 4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, well why don't you tell us how to start this one

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh, and is it \[\frac{1}{3(53x)}\] or \[\frac{1}{3}(53x)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok. So which part do you want to tackle first? (There's lots of different paths to the same answer)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Overall goal is to get all the x terms on one side and the nonx terms on the other side

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You tell me what to do, and I'll write the new equation.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[2x1= \frac{1}{3}(53x) + 4\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i don't know how to start that's why i'm asking

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's ok. Just pick a term that is in the wrong place

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We want everything with an x on the left, and everything without an x on the right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Pick a term, any term.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ah, that term is a little tricky because it's part of a factor in a product. We will need to expand that product out first before we can work with that term directly

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That just means we need to distribute the 1/3 to each of the terms in the other factor

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So what do we get when we distribute that 1/3?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no. we have to multiply each term in the left factor by 1/3 \[\frac{1}{3}(53x) = \frac{1}{3}*5  \frac{1}{3}*3x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Does that make sense? So what do we have when we simplify that product?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a(b+c) = ab + ac Right? Basic multiplicative distribution

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so would it be 5/3 x?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So now we have: \[2x1= \frac{5}{3}x + 4\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the whole thing would be : 2x1 = 5/3x+4?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can you solve from there? or do you need more help with it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, so pick a term that's in the wrong place

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how would i combine 5/3 + 4 that's the next step right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can certainly do that yes.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There is no 'next step'. There are a lot of ways to do it. If you want to do that next, go for it =)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so how do you do it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How do you add \(\frac{5}{3} + 4\)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You have to change the denominator of the 4 to match the 3 in the 5/3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We do this using the trick of multiplying by 1.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, so if we multiply by 1 we won't have changed the value, right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, so what is \(\frac{3}{3}\)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So you're saying then that if I multiply 4 by 3/3 I will still have 4?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[4\times \frac{3}{3} = \frac{4\times 3}{3} = \frac{12}{3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And 12/3 does equal 4, but it's in a different form that is now easy to add to 5/3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes so the answer would be 17/3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, the sum of those two terms would be 17/3 yes

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So we have: \[2x1= \frac{17}{3}x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then irt would be 3x1= 17/3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it would be 3x = 1 17/3?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, but I dun like mixed numbers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can you do the same trick to the 1 we did to the 4 to make it easy to add to the 17/3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x = 20/9 is correct yes.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you don't divide that by 3?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok i thought it was 3x = 1 17/3? and then you divide by 3 on both sides to get x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\(3x = 1+\frac{17}{3}\)\[\implies 3x = 1\times \frac{3}{3} + \frac{17}{3}\]\[\implies 3x = \frac{1\times 3}{3} + \frac{17}{3}\]\[\implies 3x = \frac{3}{3} + \frac{17}{3}\]\[\implies 3x = \frac{20}{3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then you divide by 3 on both sides

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but how do you divide 3 on both sides, that what i want to know

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dividing by 3 is the same as multiplying by 1/3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wouldn't the answer be different?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nope. \[3x \times \frac{1}{3} = \frac{20}{3} \times \frac{1}{3}\] \[x = \frac{20}{9} \] \[3x \div 3 = \frac{20}{3} \div 3\] \[x = 6.\bar{6}\bar{6} \div 3 = 2.\bar{2}\bar{2} = \frac{20}{9}\]
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