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anonymous

  • 5 years ago

solve for x: log(1-x) - log(8+x) = 1 I got this so far: (1-x/8+x) = 10

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  1. anonymous
    • 5 years ago
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    multiply both sides by (8+x) and post what you get.

  2. anonymous
    • 5 years ago
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    ok. (8/16+x^2) = 80+10x

  3. anonymous
    • 5 years ago
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    thats wrong i know it

  4. anonymous
    • 5 years ago
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    yup, it is catastrophically wrong.

  5. anonymous
    • 5 years ago
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    ok im retarded maybe its the caffeine buz

  6. anonymous
    • 5 years ago
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    please explain why u have to multiply by 8+x on both. why not 1-x on both?

  7. anonymous
    • 5 years ago
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    always be clear in what you are writing. use brackets to make your meaning clear. it is (1-x)/(8+x) = 10 multiply by (8+x) on both sides (1-x)*(8+x)/(8+x) = 80+10x the (8+x) cancels out in the numerator and denomiator on the left hand side, leaving 1-x = 80+10x. I trust you can take it from there?

  8. anonymous
    • 5 years ago
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    Yes thanx

  9. anonymous
    • 5 years ago
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    x=79/11

  10. anonymous
    • 5 years ago
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    you multiply by 8+x since you want to cancel it out from the denominator.

  11. anonymous
    • 5 years ago
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    - negative

  12. anonymous
    • 5 years ago
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    yes

  13. anonymous
    • 5 years ago
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    dude i just noticed, im so dumb. haha

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