anonymous
  • anonymous
solve the quadratic equation by completing square z^2 +16z + 47 =0 a. z=-8+/-sqrt17 b. z=8+sqrt17 c. z= -16 +sqrt47 d. z=8 +/- sqrt47
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
so z has a coefficient of 1
anonymous
  • anonymous
so we dont have to worry about it
anonymous
  • anonymous
i guess you prolly already know that a=1, b=16, and c=47

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anonymous
  • anonymous
but you get all the z's on one side, and the constants on the other, so you rearrange it so now the equation looks like this: z^2 + 16z = -47
anonymous
  • anonymous
now take half of the b coefficient, so (16/2) and square it, so (16/2)^2 so 8^2 = 64
anonymous
  • anonymous
add that to both sides of your new equation
anonymous
  • anonymous
so now you got z^2 + 16z + 64 = -47 + 64
anonymous
  • anonymous
now you can simplify that so its z^2 + 16z +64 = 17
anonymous
  • anonymous
now FOIL that equation on the left side there...which is simply (z + 8) (z + 8)
anonymous
  • anonymous
cuz that will make z^2 + 16z + 64 again
anonymous
  • anonymous
so basically you have (z + 8) ^2 = 17
anonymous
  • anonymous
so to get rid of the ^2 just take the square root of both sides
anonymous
  • anonymous
now u got z + 8 = sq. root 17
anonymous
  • anonymous
so then it would be -8=.- sqrt 17 is that right?
anonymous
  • anonymous
right...i was just a bit confused by your choice of answers there, but obviously C and D are wrong and since you would subtract 8 to get z by itself then there has to be a -8 in the answer, so yeah A is the right answer...maybe i'm just confusing myself cuz its written on a computer and not on paper lol
anonymous
  • anonymous
lol thanks a bunch

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