anonymous
  • anonymous
solve the quadratic equation by completing the squares 2x^2 +4x+7=0 a. x=-2+/-sqrt /2 b. no real solution c. x=-2+/-sqrt14/2 d. x=+/- sqrt7
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
No real solutions
anonymous
  • anonymous
And you can do that by looking at the discriminant
anonymous
  • anonymous
Do you know how to look at the discrimant and find whether it is real or complex?

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anonymous
  • anonymous
no i dont how is that done?
anonymous
  • anonymous
Do you want to know, or you are satisfied with the answer
anonymous
  • anonymous
lol id like to know please
dumbcow
  • dumbcow
factor out the 2 x^2 +2x +7/2 = 0 take half the second coefficient and square it (x+1)^2 -1 +7/2 = 0 (x+1)^2 = -5/2 x+1 = sqrt(-5/2) sqrt of neg num is non-real answer
myininaya
  • myininaya
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anonymous
  • anonymous
For any quadratic equation \[ax^2+bx+c\] if \[(b^2-4ac)\]<0 then the equation has no real roots
myininaya
  • myininaya
lol thats blank above
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anonymous
  • anonymous
Just remember this and it will work always
anonymous
  • anonymous
Did you understand that?
anonymous
  • anonymous
any problem?
anonymous
  • anonymous
no im reading it trying to understand thanks a bunch everyone :)
anonymous
  • anonymous
yes i get it

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