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anonymous

  • 5 years ago

solve the quadratic equation by completing the squares 2x^2 +4x+7=0 a. x=-2+/-sqrt /2 b. no real solution c. x=-2+/-sqrt14/2 d. x=+/- sqrt7

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  1. anonymous
    • 5 years ago
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    No real solutions

  2. anonymous
    • 5 years ago
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    And you can do that by looking at the discriminant

  3. anonymous
    • 5 years ago
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    Do you know how to look at the discrimant and find whether it is real or complex?

  4. anonymous
    • 5 years ago
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    no i dont how is that done?

  5. anonymous
    • 5 years ago
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    Do you want to know, or you are satisfied with the answer

  6. anonymous
    • 5 years ago
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    lol id like to know please

  7. dumbcow
    • 5 years ago
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    factor out the 2 x^2 +2x +7/2 = 0 take half the second coefficient and square it (x+1)^2 -1 +7/2 = 0 (x+1)^2 = -5/2 x+1 = sqrt(-5/2) sqrt of neg num is non-real answer

  8. myininaya
    • 5 years ago
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  9. anonymous
    • 5 years ago
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    For any quadratic equation \[ax^2+bx+c\] if \[(b^2-4ac)\]<0 then the equation has no real roots

  10. myininaya
    • 5 years ago
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    lol thats blank above

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  11. anonymous
    • 5 years ago
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    Just remember this and it will work always

  12. anonymous
    • 5 years ago
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    Did you understand that?

  13. anonymous
    • 5 years ago
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    any problem?

  14. anonymous
    • 5 years ago
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    no im reading it trying to understand thanks a bunch everyone :)

  15. anonymous
    • 5 years ago
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    yes i get it

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