solve the quadratic equation by completing the squares 2x^2 +4x+7=0 a. x=-2+/-sqrt /2 b. no real solution c. x=-2+/-sqrt14/2 d. x=+/- sqrt7

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solve the quadratic equation by completing the squares 2x^2 +4x+7=0 a. x=-2+/-sqrt /2 b. no real solution c. x=-2+/-sqrt14/2 d. x=+/- sqrt7

Mathematics
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No real solutions
And you can do that by looking at the discriminant
Do you know how to look at the discrimant and find whether it is real or complex?

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no i dont how is that done?
Do you want to know, or you are satisfied with the answer
lol id like to know please
factor out the 2 x^2 +2x +7/2 = 0 take half the second coefficient and square it (x+1)^2 -1 +7/2 = 0 (x+1)^2 = -5/2 x+1 = sqrt(-5/2) sqrt of neg num is non-real answer
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For any quadratic equation \[ax^2+bx+c\] if \[(b^2-4ac)\]<0 then the equation has no real roots
lol thats blank above
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Just remember this and it will work always
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any problem?
no im reading it trying to understand thanks a bunch everyone :)
yes i get it

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