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anonymous
 5 years ago
solve the quadratic equation by completing the squares
2x^2 +4x+7=0
a. x=2+/sqrt /2 b. no real solution c. x=2+/sqrt14/2 d. x=+/ sqrt7
anonymous
 5 years ago
solve the quadratic equation by completing the squares 2x^2 +4x+7=0 a. x=2+/sqrt /2 b. no real solution c. x=2+/sqrt14/2 d. x=+/ sqrt7

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And you can do that by looking at the discriminant

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you know how to look at the discrimant and find whether it is real or complex?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no i dont how is that done?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you want to know, or you are satisfied with the answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol id like to know please

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0factor out the 2 x^2 +2x +7/2 = 0 take half the second coefficient and square it (x+1)^2 1 +7/2 = 0 (x+1)^2 = 5/2 x+1 = sqrt(5/2) sqrt of neg num is nonreal answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For any quadratic equation \[ax^2+bx+c\] if \[(b^24ac)\]<0 then the equation has no real roots

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1lol thats blank above

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Just remember this and it will work always

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Did you understand that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no im reading it trying to understand thanks a bunch everyone :)
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