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anonymous
 5 years ago
y=x2+4 can someone help me wth this graph equation i need to find the vertex and the intercepts
anonymous
 5 years ago
y=x2+4 can someone help me wth this graph equation i need to find the vertex and the intercepts

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you mean y = x^2 + 4?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the standard parabola is y = mx+b where b is the yintercept so in your equation y = x^2 + 4 so the yintercept = 4, or (0,4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and the xintercepts are (2,0) and (2,0) by putting y=0

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0y=0^2 +4 y=4 y_intercept is 4 0 = x^2 +4 4 = x^2 No real x_intercepts vertex: a=1, b=0, c=4 x=b/2a x=0/2 = 0 y = 0^2+4 = 4 vertex: (0,4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh pellet..looks lyk an off day

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i ate a dumbcow at mcdonalds once.... with cheese and a bun and extra pickles... it was mighty tasty :)
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