y=x2+4 can someone help me wth this graph equation i need to find the vertex and the intercepts

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y=x2+4 can someone help me wth this graph equation i need to find the vertex and the intercepts

Mathematics
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do you mean y = x^2 + 4?
yes
so the standard parabola is y = mx+b where b is the y-intercept so in your equation y = x^2 + 4 so the y-intercept = 4, or (0,4)

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and the x-intercepts are (2,0) and (-2,0) by putting y=0
y=0^2 +4 y=4 y_intercept is 4 0 = x^2 +4 -4 = x^2 No real x_intercepts vertex: a=1, b=0, c=4 x=-b/2a x=0/2 = 0 y = 0^2+4 = 4 vertex: (0,4)
oh pellet..looks lyk an off day
dumbcows right
thanks everyone
i ate a dumbcow at mcdonalds once.... with cheese and a bun and extra pickles... it was mighty tasty :)

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