A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
y=x2+4 can someone help me wth this graph equation i need to find the vertex and the intercepts
anonymous
 5 years ago
y=x2+4 can someone help me wth this graph equation i need to find the vertex and the intercepts

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you mean y = x^2 + 4?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the standard parabola is y = mx+b where b is the yintercept so in your equation y = x^2 + 4 so the yintercept = 4, or (0,4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and the xintercepts are (2,0) and (2,0) by putting y=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y=0^2 +4 y=4 y_intercept is 4 0 = x^2 +4 4 = x^2 No real x_intercepts vertex: a=1, b=0, c=4 x=b/2a x=0/2 = 0 y = 0^2+4 = 4 vertex: (0,4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh pellet..looks lyk an off day

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i ate a dumbcow at mcdonalds once.... with cheese and a bun and extra pickles... it was mighty tasty :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.