## anonymous 5 years ago 2 + q^2/200 = 4000/p^2 differentiate implicitly

1. anonymous

to find dq/dp

2. anonymous

yeh still not enough info , are we meant to assume that q ia a function of p

3. anonymous

sry...q is suppose demand for a good and p is the price of the good....

4. anonymous

yeh, so q is a function of p

5. anonymous

so it is the exact same as differentiating 2 + y^2 / 200 = 4000/x^2 where y=q=dependant variable

6. anonymous

$2 + \frac{y^2}{200} = 4000x^{-2}$

7. anonymous

diff wrt x ( and x=p ) 0 + (2y / 200 ) (dy/dx ) = -8000x^-3

8. anonymous

so dy/dx = -80000x^-3 / y

9. anonymous

$\frac{dy}{dx} = \frac{-80000}{x^3 y}$

10. anonymous

now replace y with q, and x with p

11. anonymous

ohhh ok thanks very much...

12. anonymous

wait, should be 800 000 on the top

13. anonymous

8000 x100 =800 000

14. anonymous

ok cool...i undersatnd your method though thats what i needed help with....