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anonymous
 5 years ago
2 + q^2/200 = 4000/p^2 differentiate implicitly
anonymous
 5 years ago
2 + q^2/200 = 4000/p^2 differentiate implicitly

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeh still not enough info , are we meant to assume that q ia a function of p

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sry...q is suppose demand for a good and p is the price of the good....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeh, so q is a function of p

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so it is the exact same as differentiating 2 + y^2 / 200 = 4000/x^2 where y=q=dependant variable

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[2 + \frac{y^2}{200} = 4000x^{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0diff wrt x ( and x=p ) 0 + (2y / 200 ) (dy/dx ) = 8000x^3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so dy/dx = 80000x^3 / y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{dy}{dx} = \frac{80000}{x^3 y}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now replace y with q, and x with p

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohhh ok thanks very much...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait, should be 800 000 on the top

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok cool...i undersatnd your method though thats what i needed help with....
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