anonymous
  • anonymous
2 + q^2/200 = 4000/p^2 differentiate implicitly
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
to find dq/dp
anonymous
  • anonymous
yeh still not enough info , are we meant to assume that q ia a function of p
anonymous
  • anonymous
sry...q is suppose demand for a good and p is the price of the good....

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anonymous
  • anonymous
yeh, so q is a function of p
anonymous
  • anonymous
so it is the exact same as differentiating 2 + y^2 / 200 = 4000/x^2 where y=q=dependant variable
anonymous
  • anonymous
\[2 + \frac{y^2}{200} = 4000x^{-2}\]
anonymous
  • anonymous
diff wrt x ( and x=p ) 0 + (2y / 200 ) (dy/dx ) = -8000x^-3
anonymous
  • anonymous
so dy/dx = -80000x^-3 / y
anonymous
  • anonymous
\[\frac{dy}{dx} = \frac{-80000}{x^3 y}\]
anonymous
  • anonymous
now replace y with q, and x with p
anonymous
  • anonymous
ohhh ok thanks very much...
anonymous
  • anonymous
wait, should be 800 000 on the top
anonymous
  • anonymous
8000 x100 =800 000
anonymous
  • anonymous
ok cool...i undersatnd your method though thats what i needed help with....

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