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anonymous 5 years ago can anybody help me with this problem? is pre-cacul

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1. anonymous

Where is the problem?

2. anonymous

i have a question, here it goes, A butcher's scale is accurate to within 0.05 pound. A sirloin steak weights 1.14 pounds on this scale. Solve the inequality: lx-1.14l<_0.05. What does the solution interval represent?

3. anonymous

you know pre-cal?

4. anonymous

Some, thinking. the absolute value of the quantity x-1.14 must be less than ??? is that a -0.05????

5. anonymous

|x-1.14| <_ 0.05 => -(x-1.14) <_ 0.05 or (x-1.14) <_ 0.05 solve it up!

6. anonymous

no is 0.05

7. anonymous

lfcmaniac,, what goes after your last step?

8. anonymous

R, the inequality: is alraedy their, is given. lx-1.14l<_0.05

9. anonymous

see what you now have is -x + 1.14 <_ 0.05 => 1.14 - 0.05 <_ x => 1.09 <_ x or x<_ 0.05-1.14 => x<_ -1.09 because of the negative sign the inequality gets reversed, => x _> 1.09 get that ?

10. anonymous

oh yeah

11. anonymous

why is the x negative? is the adsolute value

12. anonymous

Worldboy, $|x| => \pm x$ ?

13. anonymous

what does the solution interval represents?

14. anonymous

|x-1.14|<0.05 -0.05<x-1.14<0.05 -0.05+1.14<x-1.14+1.14<0.05+1.14 1.09<x<1.19

15. anonymous

the solution interval represents that x is any number greater or equal to 1.09

16. anonymous

lfc you a teacher?

17. anonymous

R

18. anonymous

ther is a mistake, becuse is suppost to be <_, equal sign

19. anonymous

is it going to be the same result, wih with the <_ sign?

20. anonymous

the <_ is nothing but $\le$ isn't it ? and no i aint a teacher, i am just a 12th grade student :P

21. anonymous

yeah

22. anonymous

Is the problem $|x-1.14|\le0.05$

23. anonymous

nothing chnge much really,

24. anonymous

i just need to change the c, to <-

25. anonymous

maniac, how you did the sign, equal or greater?

26. anonymous

may come handy in the future?

27. anonymous

use the Equation button underneath the typing space my friend

28. anonymous

equation button ?

29. anonymous

never used it before

30. anonymous

give it a try and you'll get the knack of it soon

31. anonymous

where is the button?

32. anonymous

?

33. anonymous

you know R?

34. anonymous

Click on the Equation and then you will get a separate box to enter equations and a menu of mathematical symbols, and operators.

35. anonymous

thx

36. anonymous

omg, i going save this site as my favorite, i am going help the people who i can help.

37. anonymous

R, you help me with another problem, i am having problem?

38. anonymous

Review this problem very carefully as I think there may be an error. I come up with the answer: 1.09<x<1.19$1.09\le x \le 1.19$ Rework it and see what you get.

39. anonymous

Yes, if I can.

40. anonymous

yeah, i got the exact same thing

41. anonymous

should i write it to 1.09<_x 1.19>_x

42. anonymous

look rthe other problem i need help in, it goes like this i have a question i don't quite understand, i am preparing for a exam. A 100-gallon mixture of citrus extract and water is 3% citrus extract, and it needs to be diluted. The function f(x)=3/100+x represents the percentrage (in decimal form) of the miture that is citrus extract when x gallons of water are added. Find the domain of f(x). Then, find the percentage of citrus extract in the mixture after 50 gallons of water are added to it.

43. anonymous

i think the prof gave me a problem silimiar to this, i going check my notes

44. anonymous

O.K let me study it a bit

45. anonymous

ok

46. anonymous

I don't quite understand the function, but there is 100 gallons of mixture of which is 3% citrus or 3 gallons of citrus 97 gallons of water. It looks like they add 50 gallons of water (no more citrus) giving 150 gallolns of mixture of which only 3 gallons is citrus (since no more was added) So now the percerntage is 3/150 or only 2% citrus. Do you have the answer?

47. anonymous

no

48. anonymous

It appears the domain of x could be the set of real numbers. What bothers me is the function seems to have a constant of .03 rather than attaining a 3 % mixture. It has been over 30 years since I had Calculus and I need to brush up on it. I am afraid I am not too much help to you at this time WorldBoy

49. anonymous

is ok.

50. anonymous

you try

51. anonymous

Good luck with your studies and this "test"

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