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Where is the problem?

you know pre-cal?

Some, thinking. the absolute value of the quantity x-1.14 must be less than ??? is that a -0.05????

|x-1.14| <_ 0.05
=> -(x-1.14) <_ 0.05
or (x-1.14) <_ 0.05
solve it up!

no is 0.05

lfcmaniac,, what goes after your last step?

R, the inequality: is alraedy their, is given. lx-1.14l<_0.05

oh yeah

why is the x negative?
is the adsolute value

Worldboy, \[|x| => \pm x\] ?

what does the solution interval represents?

|x-1.14|<0.05
-0.05

the solution interval represents that x is any number greater or equal to 1.09

lfc you a teacher?

ther is a mistake, becuse is suppost to be <_, equal sign

is it going to be the same result, wih with the <_ sign?

the <_ is nothing but \[\le\] isn't it ?
and no i aint a teacher, i am just a 12th grade student :P

yeah

Is the problem \[|x-1.14|\le0.05\]

nothing chnge much really,

i just need to change the c, to <-

maniac, how you did the sign, equal or greater?

may come handy in the future?

use the Equation button underneath the typing space my friend

equation button ?

never used it before

give it a try and you'll get the knack of it soon

where is the button?

you know R?

thx

omg, i going save this site as my favorite, i am going help the people who i can help.

R, you help me with another problem, i am having problem?

Review this problem very carefully as I think there may be an error. I come up with the answer: 1.09

Yes, if I can.

yeah, i got the exact same thing

should i write it to
1.09<_x
1.19>_x

i think the prof gave me a problem silimiar to this, i going check my notes

O.K let me study it a bit

ok

no

is ok.

you try

Good luck with your studies and this "test"