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anonymous

  • 5 years ago

can anybody help me with this problem? is pre-cacul

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  1. R
    • 5 years ago
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    Where is the problem?

  2. anonymous
    • 5 years ago
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    i have a question, here it goes, A butcher's scale is accurate to within 0.05 pound. A sirloin steak weights 1.14 pounds on this scale. Solve the inequality: lx-1.14l<_0.05. What does the solution interval represent?

  3. anonymous
    • 5 years ago
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    you know pre-cal?

  4. R
    • 5 years ago
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    Some, thinking. the absolute value of the quantity x-1.14 must be less than ??? is that a -0.05????

  5. anonymous
    • 5 years ago
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    |x-1.14| <_ 0.05 => -(x-1.14) <_ 0.05 or (x-1.14) <_ 0.05 solve it up!

  6. anonymous
    • 5 years ago
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    no is 0.05

  7. anonymous
    • 5 years ago
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    lfcmaniac,, what goes after your last step?

  8. anonymous
    • 5 years ago
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    R, the inequality: is alraedy their, is given. lx-1.14l<_0.05

  9. anonymous
    • 5 years ago
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    see what you now have is -x + 1.14 <_ 0.05 => 1.14 - 0.05 <_ x => 1.09 <_ x or x<_ 0.05-1.14 => x<_ -1.09 because of the negative sign the inequality gets reversed, => x _> 1.09 get that ?

  10. anonymous
    • 5 years ago
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    oh yeah

  11. anonymous
    • 5 years ago
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    why is the x negative? is the adsolute value

  12. anonymous
    • 5 years ago
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    Worldboy, \[|x| => \pm x\] ?

  13. anonymous
    • 5 years ago
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    what does the solution interval represents?

  14. R
    • 5 years ago
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    |x-1.14|<0.05 -0.05<x-1.14<0.05 -0.05+1.14<x-1.14+1.14<0.05+1.14 1.09<x<1.19

  15. anonymous
    • 5 years ago
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    the solution interval represents that x is any number greater or equal to 1.09

  16. anonymous
    • 5 years ago
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    lfc you a teacher?

  17. anonymous
    • 5 years ago
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    R

  18. anonymous
    • 5 years ago
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    ther is a mistake, becuse is suppost to be <_, equal sign

  19. anonymous
    • 5 years ago
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    is it going to be the same result, wih with the <_ sign?

  20. anonymous
    • 5 years ago
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    the <_ is nothing but \[\le\] isn't it ? and no i aint a teacher, i am just a 12th grade student :P

  21. anonymous
    • 5 years ago
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    yeah

  22. R
    • 5 years ago
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    Is the problem \[|x-1.14|\le0.05\]

  23. anonymous
    • 5 years ago
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    nothing chnge much really,

  24. anonymous
    • 5 years ago
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    i just need to change the c, to <-

  25. anonymous
    • 5 years ago
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    maniac, how you did the sign, equal or greater?

  26. anonymous
    • 5 years ago
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    may come handy in the future?

  27. anonymous
    • 5 years ago
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    use the Equation button underneath the typing space my friend

  28. anonymous
    • 5 years ago
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    equation button ?

  29. anonymous
    • 5 years ago
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    never used it before

  30. anonymous
    • 5 years ago
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    give it a try and you'll get the knack of it soon

  31. anonymous
    • 5 years ago
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    where is the button?

  32. anonymous
    • 5 years ago
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    ?

  33. anonymous
    • 5 years ago
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    you know R?

  34. R
    • 5 years ago
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    Click on the Equation and then you will get a separate box to enter equations and a menu of mathematical symbols, and operators.

  35. anonymous
    • 5 years ago
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    thx

  36. anonymous
    • 5 years ago
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    omg, i going save this site as my favorite, i am going help the people who i can help.

  37. anonymous
    • 5 years ago
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    R, you help me with another problem, i am having problem?

  38. R
    • 5 years ago
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    Review this problem very carefully as I think there may be an error. I come up with the answer: 1.09<x<1.19\[1.09\le x \le 1.19\] Rework it and see what you get.

  39. R
    • 5 years ago
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    Yes, if I can.

  40. anonymous
    • 5 years ago
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    yeah, i got the exact same thing

  41. anonymous
    • 5 years ago
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    should i write it to 1.09<_x 1.19>_x

  42. anonymous
    • 5 years ago
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    look rthe other problem i need help in, it goes like this i have a question i don't quite understand, i am preparing for a exam. A 100-gallon mixture of citrus extract and water is 3% citrus extract, and it needs to be diluted. The function f(x)=3/100+x represents the percentrage (in decimal form) of the miture that is citrus extract when x gallons of water are added. Find the domain of f(x). Then, find the percentage of citrus extract in the mixture after 50 gallons of water are added to it.

  43. anonymous
    • 5 years ago
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    i think the prof gave me a problem silimiar to this, i going check my notes

  44. R
    • 5 years ago
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    O.K let me study it a bit

  45. anonymous
    • 5 years ago
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    ok

  46. R
    • 5 years ago
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    I don't quite understand the function, but there is 100 gallons of mixture of which is 3% citrus or 3 gallons of citrus 97 gallons of water. It looks like they add 50 gallons of water (no more citrus) giving 150 gallolns of mixture of which only 3 gallons is citrus (since no more was added) So now the percerntage is 3/150 or only 2% citrus. Do you have the answer?

  47. anonymous
    • 5 years ago
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    no

  48. R
    • 5 years ago
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    It appears the domain of x could be the set of real numbers. What bothers me is the function seems to have a constant of .03 rather than attaining a 3 % mixture. It has been over 30 years since I had Calculus and I need to brush up on it. I am afraid I am not too much help to you at this time WorldBoy

  49. anonymous
    • 5 years ago
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    is ok.

  50. anonymous
    • 5 years ago
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    you try

  51. R
    • 5 years ago
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    Good luck with your studies and this "test"

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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