anonymous
  • anonymous
(x^(-2)-y^(-2))/(x^(-1)-y^(-1)) please?
Mathematics
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[{x^{-2}-y^{-2} \over x^{-1}-y^{-1}}?\]
amistre64
  • amistre64
\[\frac{x^{-2}-y^{-2}}{x^{-1}-y^{-1}}\] right?
amistre64
  • amistre64
its just a matter of flipping all the ^- exponents to their reciprocals and re writeing it

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amistre64
  • amistre64
what part are you stuck at?
anonymous
  • anonymous
\[x ^{-1}-y ^{-1}\]
anonymous
  • anonymous
Just factor the numerator: \[={(x^{-1}-y^{-1})(x^{-1}+y^{-1}) \over x^{-1}-y^{-1}}=x^{-1}+y^{-1}\]
anonymous
  • anonymous
so is it 1/x-y
anonymous
  • anonymous
\[\frac{x^{-2}-y^{-2}}{x^{-1}-y^{-1}}=\frac{\frac{1}{x^2}-\frac{1}{y^2}}{\frac{1}{x}-\frac{1}{y}}\] Answar's ways method is the correct snappy way to do it but if you want to see why it is true, multiply numerator and denominator by \[x^2y^2\] to clear the fractions, or subtract and divide and you will get \[\frac{y-x}{xy}\]
anonymous
  • anonymous
wow, thanks satelite73! how do i give a medal for your answer? you had the clearest solution of all! made me really understand the problem well. :) THANK YOU SO MUCH TO THE OTHERS AS WELL! <3
anonymous
  • anonymous
By the way satellite, it's Anwar :) .. My way is simpler if you focus :P
anonymous
  • anonymous
you're right Anwar! it is! i guess i just have to be more focused!

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