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anonymous

  • 5 years ago

find the integral S (x/6 + 6/x) dx

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  1. anonymous
    • 5 years ago
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    You can break apart the integral

  2. anonymous
    • 5 years ago
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    \[\int\limits_{}^{}({x \over 6}+{6 \over x})dx={x^2 \over 12}+6\ln \left| x \right|+c={x^2 \over 12}+\ln (x^6) +c\]

  3. anonymous
    • 5 years ago
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    how did u get x^12/12?

  4. anonymous
    • 5 years ago
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    It's x^2/12. Because when you integration of x is x^2/2, then multiply this by 1/6, you get x^2/12.

  5. anonymous
    • 5 years ago
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    hey, anwarA. How did yu do for the fraction to appear like that ?

  6. anonymous
    • 5 years ago
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    How much would you pay for that? :P

  7. amistre64
    • 5 years ago
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    frac{}{}

  8. anonymous
    • 5 years ago
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    i'll givu a medal haha

  9. anonymous
    • 5 years ago
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    @amistre64: he/she asked me >.<

  10. amistre64
    • 5 years ago
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    lol....then answer ;) if you know how lol

  11. anonymous
    • 5 years ago
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    oh thanks amistre \[frac{1}{2}\]

  12. anonymous
    • 5 years ago
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    phail lol

  13. amistre64
    • 5 years ago
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    i left out that part where you do it in the....

  14. anonymous
    • 5 years ago
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    I'll tell you another way, a better way. "{something over something}"

  15. anonymous
    • 5 years ago
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    using the "equation" feature of course.

  16. anonymous
    • 5 years ago
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    \[1 \over 2\] oh boy thanks lo

  17. anonymous
    • 5 years ago
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    You are welcome :)

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