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anonymous
 5 years ago
find the integral S (x/6 + 6/x) dx
anonymous
 5 years ago
find the integral S (x/6 + 6/x) dx

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can break apart the integral

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{}({x \over 6}+{6 \over x})dx={x^2 \over 12}+6\ln \left x \right+c={x^2 \over 12}+\ln (x^6) +c\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did u get x^12/12?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's x^2/12. Because when you integration of x is x^2/2, then multiply this by 1/6, you get x^2/12.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey, anwarA. How did yu do for the fraction to appear like that ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How much would you pay for that? :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i'll givu a medal haha

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@amistre64: he/she asked me >.<

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1lol....then answer ;) if you know how lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh thanks amistre \[frac{1}{2}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i left out that part where you do it in the....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'll tell you another way, a better way. "{something over something}"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0using the "equation" feature of course.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[1 \over 2\] oh boy thanks lo
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