A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
Consider the solid obtained by rotating the region bounded by the given curves about the line y = 5.
y = 5x , y = 5 * squareroot of x
Find volume.
anonymous
 5 years ago
Consider the solid obtained by rotating the region bounded by the given curves about the line y = 5. y = 5x , y = 5 * squareroot of x Find volume.

This Question is Closed

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1considered....now what?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is it solid of revolution problem in calc

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, we first have to find intersections

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0have you guys ever heard of the disk or washer method to finding volume?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1first things first; whats our boundaries for integration

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you for that link :) how do you find the boundaries though?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We look the the intersection point which are (1,5)(0,0)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so would the bounaries be from 0 to 5?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So what method would you use?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the y=5 line seems spurious

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm, im not sure which method to choose

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because im looking through my notes right now, it looks like we could use the disk method

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Since you are going to be rotating around an horizontal point(y=5) you are going to use disk method( or washer)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in Some cases you can use either but it is matter convienience

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the disk method is adding up all the areas of the circles; [S] 2pi [f(x)]^2 dx  [S] 2pi [g(x)]^2 dx

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1ohhh....rotating AROUND y=5; haha :) helps to read the question lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I would advise against blindly memorizing the formula

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have in my notes that the disk method formula is pi (R(x))^2 dx

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the formula is jsut the qnqlytic representation of what you are actually accomplishing;

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1R(x)  5 in this case

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So the bigger circle have radius of 55x the smaller circle have radius of 55Sqrt[x]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i was combining the shell and the disk ....my mistake

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohh i think i get it. so would it be (55sqrt)^2(55x)^2 dx

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you simply find the volume of the outer function and cut out the volume of the inner function

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think you have it reversed

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1[5x5] ^2  [5sqrt(x)5]^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how come its that way rather than the way i put it? i remember my professor i think tellung us that its the bottom function subtracted from the top one, and in this case, the top function is the 5sqrt of x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i might be confusing it with something else x_X

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1sine y = 5; you want to bring the function down to y = 0 therefore: f(x)  5

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1since y = 5...yadayada

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1at y=5; the function is out of reach up on a shelf; you want to get it down to where you can work with it on the table.... bring it down to y=0 by subtracting 5 from it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohhh, i see what you mean now

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you guys so much for all the help but im running late for class haha so ill try to work this with what you guys helped me with so far. thank you guys times infinityy !
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.