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anonymous
 5 years ago
For the following power series determine the interval of convergence
S = (3x^2 ÷ 4 • 7) +( 5x^4 ÷ 7 • 9) + (7x^6 ÷10 • 11) + . . .
anonymous
 5 years ago
For the following power series determine the interval of convergence S = (3x^2 ÷ 4 • 7) +( 5x^4 ÷ 7 • 9) + (7x^6 ÷10 • 11) + . . .

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is it 3x^2/(4*7) OR (3x^2/4)*7?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is 3x^2/(4*7) AnwarA, I'm sorry i was doing other problems. I'll be waiting my friend

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you know how to use the ratio test?!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes i know the basics like convergence and divergence based on the value 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Let me help you first with writing the series in its standard from; \[{3x^2 \over 4(7)}+{5x^4 \over 7(9)}+{7x^6 \over 10(11)}+...=\sum_{n=1}^{\infty}{(2n+1)x^{2n} \over (3n+1)(2n+5)}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's good. Now do the test, and find the limit. Tell me what you get!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, i'm working on it now

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0all the terms cancell out and i am left with 1 which i added to Un and therfore test fails

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, actually you will be left with x. Then your interval of convergence should be x<1. That's 1<x<1. Then you should test the endpoint 1 and 1.
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