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anonymous

  • 5 years ago

0.82 = 1e^(3k) How do I solve for K?

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  1. anonymous
    • 5 years ago
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    Take ln for both sides and you're almost done.

  2. anonymous
    • 5 years ago
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    Not quite good with these, as we still didn't study logarithms in school. But I think \[\ln \] will help solve the thing.

  3. anonymous
    • 5 years ago
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    This is right Moe.

  4. anonymous
    • 5 years ago
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    Thanks mate. I'll be taking Maths Level 2 Sunject Test in a month, so I'll get to use logarthims quite a bit :)

  5. anonymous
    • 5 years ago
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    Good Luck! :)

  6. anonymous
    • 5 years ago
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    @remidia, did you get the idea here?

  7. anonymous
    • 5 years ago
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    No, this whole problem is really confusing me. The problem in its entirety is The amount of a drug in a person's bloodstream can be modeled with exponential decay. Suppose that, in 3 hours, 18% of the drug is removed from the bloodstream. What is the half-life of the drug? A) 8.1 hours B) 8.7 hours C) 9.3 hours D) 9.9 hours E) 10.5 hours

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spraguer (Moderator)
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