0.82 = 1e^(3k) How do I solve for K?

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0.82 = 1e^(3k) How do I solve for K?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Take ln for both sides and you're almost done.
Not quite good with these, as we still didn't study logarithms in school. But I think \[\ln \] will help solve the thing.
This is right Moe.

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Thanks mate. I'll be taking Maths Level 2 Sunject Test in a month, so I'll get to use logarthims quite a bit :)
Good Luck! :)
@remidia, did you get the idea here?
No, this whole problem is really confusing me. The problem in its entirety is The amount of a drug in a person's bloodstream can be modeled with exponential decay. Suppose that, in 3 hours, 18% of the drug is removed from the bloodstream. What is the half-life of the drug? A) 8.1 hours B) 8.7 hours C) 9.3 hours D) 9.9 hours E) 10.5 hours

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