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anonymous
 5 years ago
0.82 = 1e^(3k)
How do I solve for K?
anonymous
 5 years ago
0.82 = 1e^(3k) How do I solve for K?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Take ln for both sides and you're almost done.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Not quite good with these, as we still didn't study logarithms in school. But I think \[\ln \] will help solve the thing.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks mate. I'll be taking Maths Level 2 Sunject Test in a month, so I'll get to use logarthims quite a bit :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@remidia, did you get the idea here?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No, this whole problem is really confusing me. The problem in its entirety is The amount of a drug in a person's bloodstream can be modeled with exponential decay. Suppose that, in 3 hours, 18% of the drug is removed from the bloodstream. What is the halflife of the drug? A) 8.1 hours B) 8.7 hours C) 9.3 hours D) 9.9 hours E) 10.5 hours
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