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anonymous

  • 5 years ago

how do we factor (3n-2)^2 ÷ 3^n

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  1. amistre64
    • 5 years ago
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    exapnd it out

  2. anonymous
    • 5 years ago
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    \[{(3n-2)^{2} \over 3^{n}} \]\[{(9n^{2} - 12n +4) \over (3^{n})} \] that's all i can get.. is that what it is ?

  3. amistre64
    • 5 years ago
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    3n^2 -12n +4 ------------- you sure you typed it right? 3^n

  4. amistre64
    • 5 years ago
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    9n^2...doh!

  5. anonymous
    • 5 years ago
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    hehe it happens lol

  6. amistre64
    • 5 years ago
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    we can try taking the log of this stuff if so

  7. amistre64
    • 5 years ago
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    umm...why did we expand to get factors :) seems backwards eh

  8. anonymous
    • 5 years ago
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    don't you need an equal to log it out ?

  9. anonymous
    • 5 years ago
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    thank you MathMind and amistre64, helpfull indeed

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