anonymous
  • anonymous
how do we factor (3n-2)^2 ÷ 3^n
Mathematics
jamiebookeater
  • jamiebookeater
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amistre64
  • amistre64
exapnd it out
anonymous
  • anonymous
\[{(3n-2)^{2} \over 3^{n}} \]\[{(9n^{2} - 12n +4) \over (3^{n})} \] that's all i can get.. is that what it is ?
amistre64
  • amistre64
3n^2 -12n +4 ------------- you sure you typed it right? 3^n

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amistre64
  • amistre64
9n^2...doh!
anonymous
  • anonymous
hehe it happens lol
amistre64
  • amistre64
we can try taking the log of this stuff if so
amistre64
  • amistre64
umm...why did we expand to get factors :) seems backwards eh
anonymous
  • anonymous
don't you need an equal to log it out ?
anonymous
  • anonymous
thank you MathMind and amistre64, helpfull indeed

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