The present population, P, in thousands, of a town is related to the initial population of the town at time t = 0 by the formulaP = 185(2)(0.05t)where t is measured in years. The town was populated in 1880. What was the population (to the nearest 1,000) in the year 2000?

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The present population, P, in thousands, of a town is related to the initial population of the town at time t = 0 by the formulaP = 185(2)(0.05t)where t is measured in years. The town was populated in 1880. What was the population (to the nearest 1,000) in the year 2000?

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Is formula 185*2*0.05t
?
no im sorry the formula is 185(2)^(0.05t)

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I think you mean: P(t) = \[185(2)^{(0.05t)}\] so if you subtract 2000-1880 to get t then substitute that into the equation.
t should be 120 120*.05 = 6 2^6 = 64 185*64 = 11840 people
or 12,000 people if you round
okay just to double check your answer, heres additional informatio. the population of the year 1880 was 185,000
then in that case set 1880= 185(2)^(0.05t) and solve for t. Add 120 to the t value and substitute that value back into the P(t)
and what did u come up with because im stuck
from 1880 to 2000, 120 years have passed so this will be the t_value you use to evaluate the population in year 2000 \[P = 185*2^{.05*120}\] \[P = 185*2^{6}\] \[P = 11,840\] since this is in thousands add 3 zeroes
wouldnt you add 11,840 to the population 185,000 because thats how much the popultion increased over 120 years?
no because we left the 185 in the equation their initial population is already factored in the increase would be 11,840 - 185
in other words the equation gives population at any time t not just the increase
damn. well then maybe idid it wrong and maybe the population of 1880 isnt 185,000 .....ughh im confusing myself.
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If what you posted above is correct then yes when t=0 in 1880 the population is 185,000

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