8z^2-64 when factored out does this equal 8(z-8)(z+8)

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8z^2-64 when factored out does this equal 8(z-8)(z+8)

Mathematics
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8 ( z^2 - 8 )
when you factor out the 8 you need to divide the 64 by 8 as well
its just a matter of taking the time to multiply it all together again; you can do it :)

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Other answers:

so when i multiply it all back out it gives me my 8z^2-64 ohhhh ok lol im just trying to get other peoples opinions o my answers and check my answers for an assighnment i have
(2z sqrt(2) +8) (2z sqrt(2) -8) is what i get
8.8.8 > 64
we arent supposed to use the quadratic equation we dont learn that til junior year
this factors to a difference of squares
your original conclusion there is wrong
but when i multiply it all back it gives me the original equation
?
what would it equal then cause its confusing me
\[= 8 ( z^2 -8 )\]\[= 8 ( z-\sqrt{8})(z+\sqrt{8})\]
thats it , noting else
or you could write it as \[8 ( z-2\sqrt{2})(z+2\sqrt{2})\] as \[\sqrt{8} = \sqrt{4 \times 2} = \sqrt{4} \times \sqrt{2} = 2\sqrt{2}\]

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