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anonymous

  • 5 years ago

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  1. anonymous
    • 5 years ago
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    8

  2. anonymous
    • 5 years ago
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    g(x)=x\[\sqrt{2-x}\] Use a graphing utility to approximate the relative minimum or relative maximum value of the function

  3. anonymous
    • 5 years ago
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    V2-x goes next to =x

  4. amistre64
    • 5 years ago
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    square roots dont have a relative min or max..... unless its their endpoints

  5. anonymous
    • 5 years ago
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    it does but the end point is not giving

  6. amistre64
    • 5 years ago
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    youre going to have to rewrite the question to make sense of it for us :)

  7. anonymous
    • 5 years ago
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    so is infinitY/

  8. anonymous
    • 5 years ago
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    ok

  9. anonymous
    • 5 years ago
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    \[g(x)=\sqrt{2-x}\]

  10. anonymous
    • 5 years ago
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    and x is next to V2-x

  11. anonymous
    • 5 years ago
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    so is g(x)=xV(2-x)

  12. dumbcow
    • 5 years ago
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    domain is x<=2 relative maximum at x=4/3 i used calculus and set derivative equal to 0

  13. anonymous
    • 5 years ago
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    relative maximum at x=4/3, why not a cordinate?

  14. dumbcow
    • 5 years ago
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    to get y coordinate substitute 4/3 for x y = 4/3 * sqrt(2-4/3)

  15. anonymous
    • 5 years ago
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    so you get, g(4/3)=4/3V(2-3/4)

  16. dumbcow
    • 5 years ago
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    you need to find a graphing calculator or grAPHING COMPUTER software to see it visually which i think is what the question is asking

  17. anonymous
    • 5 years ago
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    yeah, the is what it asking but like somebody above said, square root fuction don't have a maximun or minimum. Then how you find it?

  18. dumbcow
    • 5 years ago
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    no they dont but g(x) does because it has the x out front of the sqrt

  19. anonymous
    • 5 years ago
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    i don't got a graphing calculator

  20. anonymous
    • 5 years ago
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    and i search in the internet,but din't find any that could graph square root functions

  21. dumbcow
    • 5 years ago
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    try this http://www.graphcalc.com/download.shtml

  22. anonymous
    • 5 years ago
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    i got a similar problem, with the answe,r wanna me to show you?

  23. anonymous
    • 5 years ago
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    i am using schoool computer , cannot dowload the.

  24. dumbcow
    • 5 years ago
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    ok, is this a calculus class?

  25. anonymous
    • 5 years ago
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    pre

  26. dumbcow
    • 5 years ago
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    ok for last problem you def need the graph or plot the points from 0 to 2 to see the maximum

  27. anonymous
    • 5 years ago
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    did you dowload the graph program?

  28. dumbcow
    • 5 years ago
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    yeah i used it to graph your function:)

  29. anonymous
    • 5 years ago
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    what did you get?

  30. anonymous
    • 5 years ago
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    the domain, is x<_2 , right?

  31. dumbcow
    • 5 years ago
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    yes here is the graph

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  32. anonymous
    • 5 years ago
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    oh, it looks different from what i thought it would be .

  33. dumbcow
    • 5 years ago
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    thats because of the x in front

  34. anonymous
    • 5 years ago
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    nice., so what does the x do? slope>?

  35. anonymous
    • 5 years ago
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    ?

  36. anonymous
    • 5 years ago
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    what are the point of the maximun

  37. dumbcow
    • 5 years ago
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    kinda, it changes the direction of the graph when sqrt(2-x) might be decreasing as x increases when you multiply by x, it increases to a point the max is the highest point on graph, x=4/3

  38. anonymous
    • 5 years ago
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    cordinate?

  39. dumbcow
    • 5 years ago
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    i told you earlier, plug in 4/3 into function look at cursor position on right side of picture i left it at approx where the max is

  40. anonymous
    • 5 years ago
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    so it be (1.37,?

  41. anonymous
    • 5 years ago
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    use trace on the graph, to find the highest point.

  42. anonymous
    • 5 years ago
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    use trace on the graph, to find the highest point.

  43. dumbcow
    • 5 years ago
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    yes something like that

  44. anonymous
    • 5 years ago
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    i need the exact point.

  45. dumbcow
    • 5 years ago
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    from a graph you will only get an approximate but thats all you need right now the exact answer i already told you max: (4/3, 4/3*sqrt(2-(4/3)))

  46. anonymous
    • 5 years ago
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    don't got a caclculator iwth me, bye, i will solve it when ig et home.

  47. dumbcow
    • 5 years ago
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    wow y = 1.088

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