anonymous 5 years ago Consider the following.

1. anonymous

8

2. anonymous

g(x)=x$\sqrt{2-x}$ Use a graphing utility to approximate the relative minimum or relative maximum value of the function

3. anonymous

V2-x goes next to =x

4. amistre64

square roots dont have a relative min or max..... unless its their endpoints

5. anonymous

it does but the end point is not giving

6. amistre64

youre going to have to rewrite the question to make sense of it for us :)

7. anonymous

so is infinitY/

8. anonymous

ok

9. anonymous

$g(x)=\sqrt{2-x}$

10. anonymous

and x is next to V2-x

11. anonymous

so is g(x)=xV(2-x)

12. anonymous

domain is x<=2 relative maximum at x=4/3 i used calculus and set derivative equal to 0

13. anonymous

relative maximum at x=4/3, why not a cordinate?

14. anonymous

to get y coordinate substitute 4/3 for x y = 4/3 * sqrt(2-4/3)

15. anonymous

so you get, g(4/3)=4/3V(2-3/4)

16. anonymous

you need to find a graphing calculator or grAPHING COMPUTER software to see it visually which i think is what the question is asking

17. anonymous

yeah, the is what it asking but like somebody above said, square root fuction don't have a maximun or minimum. Then how you find it?

18. anonymous

no they dont but g(x) does because it has the x out front of the sqrt

19. anonymous

i don't got a graphing calculator

20. anonymous

and i search in the internet,but din't find any that could graph square root functions

21. anonymous
22. anonymous

i got a similar problem, with the answe,r wanna me to show you?

23. anonymous

i am using schoool computer , cannot dowload the.

24. anonymous

ok, is this a calculus class?

25. anonymous

pre

26. anonymous

ok for last problem you def need the graph or plot the points from 0 to 2 to see the maximum

27. anonymous

did you dowload the graph program?

28. anonymous

yeah i used it to graph your function:)

29. anonymous

what did you get?

30. anonymous

the domain, is x<_2 , right?

31. anonymous

yes here is the graph

32. anonymous

oh, it looks different from what i thought it would be .

33. anonymous

thats because of the x in front

34. anonymous

nice., so what does the x do? slope>?

35. anonymous

?

36. anonymous

what are the point of the maximun

37. anonymous

kinda, it changes the direction of the graph when sqrt(2-x) might be decreasing as x increases when you multiply by x, it increases to a point the max is the highest point on graph, x=4/3

38. anonymous

cordinate?

39. anonymous

i told you earlier, plug in 4/3 into function look at cursor position on right side of picture i left it at approx where the max is

40. anonymous

so it be (1.37,?

41. anonymous

use trace on the graph, to find the highest point.

42. anonymous

use trace on the graph, to find the highest point.

43. anonymous

yes something like that

44. anonymous

i need the exact point.

45. anonymous

from a graph you will only get an approximate but thats all you need right now the exact answer i already told you max: (4/3, 4/3*sqrt(2-(4/3)))

46. anonymous

don't got a caclculator iwth me, bye, i will solve it when ig et home.

47. anonymous

wow y = 1.088