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anonymous

  • 5 years ago

it looks long but im just explaining what i did and can someone please tell me where i went wrong??? PLEASE? ok, a sector of a circle of radius 6 cm has an angle of 1.6 radians find the area for the sector hence find the area of the segment The problem is that i worked out the area which is 28.8 of the sector i worked out the triangle and took it away from the area of the sector and ended up with 10.8 which is right but then here's the problem how do you use the formula of the area of the sector? it 1/2x6^2xsin(1.6)=0.50258... but that not what i got above i got 10.8 above :S

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  1. amistre64
    • 5 years ago
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    the area of a sector is the same as that of a circle; you just replace the angle measurement... 2pi r^2 ------- = area circle 2 angle r^2 -------- = area any part of a circle 2

  2. amistre64
    • 5 years ago
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    1.8pi 6^2 ------- = .9pi(36) = 32.4 pi 2

  3. amistre64
    • 5 years ago
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    ack!!...forget the pi part lol

  4. amistre64
    • 5 years ago
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    32.4

  5. anonymous
    • 5 years ago
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    so is the formula wrong then?

  6. amistre64
    • 5 years ago
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    dunno; but my inputs are dyslexic... 1.6 (36) ------- = area of sector 2

  7. amistre64
    • 5 years ago
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    .8(36) = 28.8

  8. anonymous
    • 5 years ago
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    but thats a different answer :( so is 10.8 wrong then??

  9. amistre64
    • 5 years ago
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    why are you removing the area of the triangle?

  10. anonymous
    • 5 years ago
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    to get the segment area and i looked at the mark scheme and 10.8 is right but theres a segemnt area formula and that doesnt work :(

  11. amistre64
    • 5 years ago
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    so teh segment will be the arch looking section of the piece of pie right?

  12. amistre64
    • 5 years ago
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    the area of a trianlge is: r^2 sin(angle) ------------ 2

  13. amistre64
    • 5 years ago
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    make sure you have your calculator set to radians tho

  14. anonymous
    • 5 years ago
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    sin?? isnt area of a traingle BxH/2???

  15. amistre64
    • 5 years ago
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    it is; but this isnt the area of a right triangle

  16. anonymous
    • 5 years ago
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    oh :o

  17. amistre64
    • 5 years ago
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    the area of any triangle is: base = radial arm = 6 height = radial arm *sin(a) = 6 sin(1.6) and /2 sooo... 36 sin(1.6) --------- = 18 sin(1.6) 2

  18. amistre64
    • 5 years ago
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    the area of the tri is abt: 17.99

  19. anonymous
    • 5 years ago
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    here is the diagram, if u need it

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  20. amistre64
    • 5 years ago
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    28.8 -17.99 ------- 10.81

  21. amistre64
    • 5 years ago
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    or maybe not..... is 1.2 larger than 90?

  22. anonymous
    • 5 years ago
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    1.2 lager than 90??? is this a trick qs?

  23. amistre64
    • 5 years ago
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    1.2 * 180 -------- = 68.75 degrees right? pi

  24. anonymous
    • 5 years ago
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    yes, but now im lost where did you get these number fomr?

  25. amistre64
    • 5 years ago
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    trying to convert radians to degrees; radians normally have a pi in them so you multiply by 180/pi to get the angle.. pi 180 -- * ----- = 90 degrees 2 pi

  26. amistre64
    • 5 years ago
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    12 180 --- * ---- = 216/pi = 68.75 10 pi

  27. anonymous
    • 5 years ago
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    oh :o

  28. amistre64
    • 5 years ago
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    since the angle is acute; we can assume that our method was correct;

  29. amistre64
    • 5 years ago
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    so I get 10.81 whats the answer you get?

  30. anonymous
    • 5 years ago
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    10.8 :)

  31. amistre64
    • 5 years ago
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    then the area of the segment should be 10.8 :)

  32. anonymous
    • 5 years ago
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    thank you soo much for explaining this :) if i could i would have wanted to give you some more medals but i can only give you one :S

  33. amistre64
    • 5 years ago
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    'sok; you enjoy yourself now :) i got class starting soon

  34. anonymous
    • 5 years ago
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    bye bye :)

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