anonymous
  • anonymous
it looks long but im just explaining what i did and can someone please tell me where i went wrong??? PLEASE? ok, a sector of a circle of radius 6 cm has an angle of 1.6 radians find the area for the sector hence find the area of the segment The problem is that i worked out the area which is 28.8 of the sector i worked out the triangle and took it away from the area of the sector and ended up with 10.8 which is right but then here's the problem how do you use the formula of the area of the sector? it 1/2x6^2xsin(1.6)=0.50258... but that not what i got above i got 10.8 above :S
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
amistre64
  • amistre64
the area of a sector is the same as that of a circle; you just replace the angle measurement... 2pi r^2 ------- = area circle 2 angle r^2 -------- = area any part of a circle 2
amistre64
  • amistre64
1.8pi 6^2 ------- = .9pi(36) = 32.4 pi 2
amistre64
  • amistre64
ack!!...forget the pi part lol

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amistre64
  • amistre64
32.4
anonymous
  • anonymous
so is the formula wrong then?
amistre64
  • amistre64
dunno; but my inputs are dyslexic... 1.6 (36) ------- = area of sector 2
amistre64
  • amistre64
.8(36) = 28.8
anonymous
  • anonymous
but thats a different answer :( so is 10.8 wrong then??
amistre64
  • amistre64
why are you removing the area of the triangle?
anonymous
  • anonymous
to get the segment area and i looked at the mark scheme and 10.8 is right but theres a segemnt area formula and that doesnt work :(
amistre64
  • amistre64
so teh segment will be the arch looking section of the piece of pie right?
amistre64
  • amistre64
the area of a trianlge is: r^2 sin(angle) ------------ 2
amistre64
  • amistre64
make sure you have your calculator set to radians tho
anonymous
  • anonymous
sin?? isnt area of a traingle BxH/2???
amistre64
  • amistre64
it is; but this isnt the area of a right triangle
anonymous
  • anonymous
oh :o
amistre64
  • amistre64
the area of any triangle is: base = radial arm = 6 height = radial arm *sin(a) = 6 sin(1.6) and /2 sooo... 36 sin(1.6) --------- = 18 sin(1.6) 2
amistre64
  • amistre64
the area of the tri is abt: 17.99
anonymous
  • anonymous
here is the diagram, if u need it
1 Attachment
amistre64
  • amistre64
28.8 -17.99 ------- 10.81
amistre64
  • amistre64
or maybe not..... is 1.2 larger than 90?
anonymous
  • anonymous
1.2 lager than 90??? is this a trick qs?
amistre64
  • amistre64
1.2 * 180 -------- = 68.75 degrees right? pi
anonymous
  • anonymous
yes, but now im lost where did you get these number fomr?
amistre64
  • amistre64
trying to convert radians to degrees; radians normally have a pi in them so you multiply by 180/pi to get the angle.. pi 180 -- * ----- = 90 degrees 2 pi
amistre64
  • amistre64
12 180 --- * ---- = 216/pi = 68.75 10 pi
anonymous
  • anonymous
oh :o
amistre64
  • amistre64
since the angle is acute; we can assume that our method was correct;
amistre64
  • amistre64
so I get 10.81 whats the answer you get?
anonymous
  • anonymous
10.8 :)
amistre64
  • amistre64
then the area of the segment should be 10.8 :)
anonymous
  • anonymous
thank you soo much for explaining this :) if i could i would have wanted to give you some more medals but i can only give you one :S
amistre64
  • amistre64
'sok; you enjoy yourself now :) i got class starting soon
anonymous
  • anonymous
bye bye :)

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