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anonymous

  • 5 years ago

Solve this inequality and write the answer in interval notation: (4)/(x-3)-(1)/(2x)≥0

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  1. anonymous
    • 5 years ago
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    Do what you said before.. Put them over a common denominator.

  2. dumbcow
    • 5 years ago
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    combine fractions common denominator is (x-3)(2x) 8x-(x-3) / 2x(x-3) >=0 simplifies to 7x+3 >= 0 7x >= -3 x >= -3/7

  3. anonymous
    • 5 years ago
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    thank you. at least someone knows how to show their work.

  4. anonymous
    • 5 years ago
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    Nobody cares if WE know how to do it. The question is do YOU know how to do it. If not then you will have to learn. And you won't do that by simply following along someone else's thought process.

  5. anonymous
    • 5 years ago
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    i think i will lol

  6. anonymous
    • 5 years ago
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    no im kidding. your right

  7. anonymous
    • 5 years ago
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    Really? Cause dumbcow's answer is wrong. And if you write it down then you are also wrong.

  8. anonymous
    • 5 years ago
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    if his answer is wrong, then what is the right answer?

  9. dumbcow
    • 5 years ago
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    very true... repeat these steps on your own to practice

  10. anonymous
    • 5 years ago
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    What we said the last time you asked this.. \([-3/7, 0) \bigcup (3,\infty)\)

  11. anonymous
    • 5 years ago
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    And you wanted us to show work. But I would rather walk you through the process of finding the answer yourself. I think it will be more instructive.

  12. anonymous
    • 5 years ago
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    that answer is different than the answer you gave me last time, so how do i know that your answer is right?

  13. anonymous
    • 5 years ago
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    I didn't give you an answer last time. Someone else did. I didn't check it because I figured you wanted to work it out anyway.

  14. anonymous
    • 5 years ago
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    Do you want to work it out? This is why it doesn't help for someone else to show you their work. You have to work it out for yourself or you cannot be sure that the answer is correct.

  15. dumbcow
    • 5 years ago
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    no polpak is correct, i didn't look at conditions for denominator being 0

  16. anonymous
    • 5 years ago
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    ok. so can you show me the work on how to do it right

  17. anonymous
    • 5 years ago
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    Certainly.

  18. anonymous
    • 5 years ago
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    Start again with: \[\frac{4}{x-3} - \frac{1}{2x} \ge 0\] And put the fractions over a common denominator

  19. anonymous
    • 5 years ago
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    ok

  20. anonymous
    • 5 years ago
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    What do you have?

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