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## anonymous 5 years ago Solve this inequality and write the answer in interval notation: (4)/(x-3)-(1)/(2x)≥0

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1. anonymous

Do what you said before.. Put them over a common denominator.

2. dumbcow

combine fractions common denominator is (x-3)(2x) 8x-(x-3) / 2x(x-3) >=0 simplifies to 7x+3 >= 0 7x >= -3 x >= -3/7

3. anonymous

thank you. at least someone knows how to show their work.

4. anonymous

Nobody cares if WE know how to do it. The question is do YOU know how to do it. If not then you will have to learn. And you won't do that by simply following along someone else's thought process.

5. anonymous

i think i will lol

6. anonymous

no im kidding. your right

7. anonymous

Really? Cause dumbcow's answer is wrong. And if you write it down then you are also wrong.

8. anonymous

if his answer is wrong, then what is the right answer?

9. dumbcow

very true... repeat these steps on your own to practice

10. anonymous

What we said the last time you asked this.. $$[-3/7, 0) \bigcup (3,\infty)$$

11. anonymous

And you wanted us to show work. But I would rather walk you through the process of finding the answer yourself. I think it will be more instructive.

12. anonymous

that answer is different than the answer you gave me last time, so how do i know that your answer is right?

13. anonymous

I didn't give you an answer last time. Someone else did. I didn't check it because I figured you wanted to work it out anyway.

14. anonymous

Do you want to work it out? This is why it doesn't help for someone else to show you their work. You have to work it out for yourself or you cannot be sure that the answer is correct.

15. dumbcow

no polpak is correct, i didn't look at conditions for denominator being 0

16. anonymous

ok. so can you show me the work on how to do it right

17. anonymous

Certainly.

18. anonymous

Start again with: $\frac{4}{x-3} - \frac{1}{2x} \ge 0$ And put the fractions over a common denominator

19. anonymous

ok

20. anonymous

What do you have?

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