anonymous
  • anonymous
Check my work please: dy/dx of Ln[x*y^2]=24 is -2x/y
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
dy/dx = -2xy
anonymous
  • anonymous
i got something really different are you trying to find y' ?
anonymous
  • anonymous
d/dx (xy^2) = d/dx(y), (x)(2y(dy/dx)) + (y^2)(1) = 0, 2xy(dy/dx + y^2 = 0, 2xy(dy/dx) = -y^2

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anonymous
  • anonymous
oops in the first part, d/dx(xy^2) = d/dx(24)* my bad
anonymous
  • anonymous
\[\ln (xy^{2}) = 24\]find dy/dx
anonymous
  • anonymous
thats it
anonymous
  • anonymous
ur answer is -2xy
anonymous
  • anonymous
what did you do with the natural log Ln ?
anonymous
  • anonymous
im sry, so stupid
anonymous
  • anonymous
forgot it
anonymous
  • anonymous
hehe it happens
anonymous
  • anonymous
thank you MathMind
anonymous
  • anonymous
-y/ 2x
anonymous
  • anonymous
thats the correct answer

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