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anonymous

  • 5 years ago

I'm trying to figure out the steps to factoring, such as the 1st problem... 2x^2y-6xy^2

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  1. anonymous
    • 5 years ago
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    Each of the terms \(2x^2y\) and \(-6xy^2\) are products of some factors. The first step is to see what factors they have in common.

  2. anonymous
    • 5 years ago
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    What are the factors you can see in both those terms?

  3. anonymous
    • 5 years ago
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    would it be 2?

  4. anonymous
    • 5 years ago
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    2 is one of the factors they have in common. There are 2 more though.

  5. anonymous
    • 5 years ago
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    I was thinking 2 because 2 goes into 2 one time, and 2 goes into 6, 3 times. The only other common factor I can see if it has something to do with x & y.

  6. anonymous
    • 5 years ago
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    yep.

  7. anonymous
    • 5 years ago
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    So would I divide both sides by 2xy?

  8. anonymous
    • 5 years ago
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    Yes, and bring that 2xy out in front.

  9. anonymous
    • 5 years ago
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    (xy)(3xy) ?

  10. anonymous
    • 5 years ago
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    2xy-(3xy) ?

  11. anonymous
    • 5 years ago
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    No, sorry. Factor out 2xy from \(2x^2y\) and \(-6xy^2\) You should have 2xy(x - 3y)

  12. anonymous
    • 5 years ago
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    And you can see if you redistribute the 2xy that you will get what you started with.

  13. anonymous
    • 5 years ago
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    ok, it's making a little bit more sense. How does the 2nd part of the answer become (x-3y) where the x is separated from the y?

  14. anonymous
    • 5 years ago
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    Each of those terms x and -3y are what's left over when you pull out the 2xy factor from both of them.

  15. anonymous
    • 5 years ago
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    Just like factoring (15 - 25) into 5(3-5)

  16. anonymous
    • 5 years ago
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    ok, I think I got it. You've been awesome. :) Thank you for your help.

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