anonymous
  • anonymous
I'm trying to figure out the steps to factoring, such as the 1st problem... 2x^2y-6xy^2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Each of the terms \(2x^2y\) and \(-6xy^2\) are products of some factors. The first step is to see what factors they have in common.
anonymous
  • anonymous
What are the factors you can see in both those terms?
anonymous
  • anonymous
would it be 2?

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anonymous
  • anonymous
2 is one of the factors they have in common. There are 2 more though.
anonymous
  • anonymous
I was thinking 2 because 2 goes into 2 one time, and 2 goes into 6, 3 times. The only other common factor I can see if it has something to do with x & y.
anonymous
  • anonymous
yep.
anonymous
  • anonymous
So would I divide both sides by 2xy?
anonymous
  • anonymous
Yes, and bring that 2xy out in front.
anonymous
  • anonymous
(xy)(3xy) ?
anonymous
  • anonymous
2xy-(3xy) ?
anonymous
  • anonymous
No, sorry. Factor out 2xy from \(2x^2y\) and \(-6xy^2\) You should have 2xy(x - 3y)
anonymous
  • anonymous
And you can see if you redistribute the 2xy that you will get what you started with.
anonymous
  • anonymous
ok, it's making a little bit more sense. How does the 2nd part of the answer become (x-3y) where the x is separated from the y?
anonymous
  • anonymous
Each of those terms x and -3y are what's left over when you pull out the 2xy factor from both of them.
anonymous
  • anonymous
Just like factoring (15 - 25) into 5(3-5)
anonymous
  • anonymous
ok, I think I got it. You've been awesome. :) Thank you for your help.

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