I'm trying to figure out the steps to factoring, such as the 1st problem... 2x^2y-6xy^2

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I'm trying to figure out the steps to factoring, such as the 1st problem... 2x^2y-6xy^2

Mathematics
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Each of the terms \(2x^2y\) and \(-6xy^2\) are products of some factors. The first step is to see what factors they have in common.
What are the factors you can see in both those terms?
would it be 2?

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2 is one of the factors they have in common. There are 2 more though.
I was thinking 2 because 2 goes into 2 one time, and 2 goes into 6, 3 times. The only other common factor I can see if it has something to do with x & y.
yep.
So would I divide both sides by 2xy?
Yes, and bring that 2xy out in front.
(xy)(3xy) ?
2xy-(3xy) ?
No, sorry. Factor out 2xy from \(2x^2y\) and \(-6xy^2\) You should have 2xy(x - 3y)
And you can see if you redistribute the 2xy that you will get what you started with.
ok, it's making a little bit more sense. How does the 2nd part of the answer become (x-3y) where the x is separated from the y?
Each of those terms x and -3y are what's left over when you pull out the 2xy factor from both of them.
Just like factoring (15 - 25) into 5(3-5)
ok, I think I got it. You've been awesome. :) Thank you for your help.

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