anonymous
  • anonymous
anyone have questions ask me :D
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
I have one!
anonymous
  • anonymous
and what is it?
myininaya
  • myininaya
no you cannot go to the bathroom

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More answers

anonymous
  • anonymous
How could you position 100 circles to intersect the maximum number of times?
anonymous
  • anonymous
your teacher must be a feather cuz i dont know that one
anonymous
  • anonymous
lol
anonymous
  • anonymous
lol
anonymous
  • anonymous
no ideas on how to start it?
anonymous
  • anonymous
I think it's a good question dinabina. Does the question say anything about radius of the circles; are they all of the same size?
anonymous
  • anonymous
Nothing that all it asks... thats why I am not sure where to begin.
anonymous
  • anonymous
same radius but different centers... I think that is used to throw me off tho...
anonymous
  • anonymous
well, the question is actually asking you, somehow, to determine the center!
anonymous
  • anonymous
centers*
anonymous
  • anonymous
I do know a circle intersects another circle twice
anonymous
  • anonymous
If all circles have the same radius, then they intersect maximum number of times, when you put each one in the top of the others.
anonymous
  • anonymous
Do you think this will be a formula answer?
anonymous
  • anonymous
Does my last answer make sense to you?
anonymous
  • anonymous
umm...they intersect maximum number of times?... no
anonymous
  • anonymous
What is an intersection?!
anonymous
  • anonymous
cross.. meet at a point
anonymous
  • anonymous
if you have circle 1 with the same radius as circle 2. And you draw circle with the same center as circle 2. Then they will have infinitely many intersection points; they actually intersect for all points in the two circles.
anonymous
  • anonymous
ok yes... that makes sense
anonymous
  • anonymous
That's only valid if they have the same radius.
anonymous
  • anonymous
If they are with different radii, then they will not intersect at all when they have the same center.
anonymous
  • anonymous
How are you figuring this out? Are these rules of circles?
anonymous
  • anonymous
Not really, just think about it. It's very clear.
anonymous
  • anonymous
ok so these are same radius different centers... how would I poistion 100 circles?
anonymous
  • anonymous
oh the question says they have to have different centers?!
anonymous
  • anonymous
Is this going to be a picture answer or a formula answer?..... yeah same radius different centers.... but the question just says how would you position 100 circles to intersect the maximum number of times.
anonymous
  • anonymous
It was an a., b., c. type question. so I am not sure if it even pertains
anonymous
  • anonymous
I think the max will be if all of them intersect at the center of some other circle.
anonymous
  • anonymous
I would roughly say that each circuit has to intersect the others at two points.
anonymous
  • anonymous
each one of the other circuits at two points*
anonymous
  • anonymous
Is the question asking about the number of maximum intersection points?
anonymous
  • anonymous
no just how to position 100 circles to intersect the maximum number of times
anonymous
  • anonymous
Ok, as I say in a position such that each circuit would intersect twice with each one of the 99 remaining circuits.
anonymous
  • anonymous
I am not sure of that answers the question.
anonymous
  • anonymous
ok... I understand that....
anonymous
  • anonymous
What do you think polpak?
anonymous
  • anonymous
One sec
anonymous
  • anonymous
Take your time!
anonymous
  • anonymous
number of total points of intersection of n congruent circles = 2C(n, 2) 100 circles intersect in 2C(100, 2) = 400 points Does this look wack?
anonymous
  • anonymous
100 times 2 = 200 a circles intersects twice... ???
anonymous
  • anonymous
i hax a question
anonymous
  • anonymous
Ok, so I think for positioning them you just have to arrange their centers around some point at intervals of \(2\pi/100\) radians a distance less than r from that point (where r is the radius of each circle).
anonymous
  • anonymous
that will space them evenly at any rate.
anonymous
  • anonymous
i haz a question, can you answer it plzzz????
anonymous
  • anonymous
while still having each circle intersecting each other circle twice.
anonymous
  • anonymous
Oh wow... so would that formula be the answer or plug in the numbers
anonymous
  • anonymous
Thank you

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