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anonymous

  • 5 years ago

anyone have questions ask me :D

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  1. anonymous
    • 5 years ago
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    I have one!

  2. anonymous
    • 5 years ago
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    and what is it?

  3. myininaya
    • 5 years ago
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    no you cannot go to the bathroom

  4. anonymous
    • 5 years ago
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    How could you position 100 circles to intersect the maximum number of times?

  5. anonymous
    • 5 years ago
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    your teacher must be a feather cuz i dont know that one

  6. anonymous
    • 5 years ago
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    lol

  7. anonymous
    • 5 years ago
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    lol

  8. anonymous
    • 5 years ago
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    no ideas on how to start it?

  9. anonymous
    • 5 years ago
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    I think it's a good question dinabina. Does the question say anything about radius of the circles; are they all of the same size?

  10. anonymous
    • 5 years ago
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    Nothing that all it asks... thats why I am not sure where to begin.

  11. anonymous
    • 5 years ago
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    same radius but different centers... I think that is used to throw me off tho...

  12. anonymous
    • 5 years ago
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    well, the question is actually asking you, somehow, to determine the center!

  13. anonymous
    • 5 years ago
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    centers*

  14. anonymous
    • 5 years ago
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    I do know a circle intersects another circle twice

  15. anonymous
    • 5 years ago
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    If all circles have the same radius, then they intersect maximum number of times, when you put each one in the top of the others.

  16. anonymous
    • 5 years ago
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    Do you think this will be a formula answer?

  17. anonymous
    • 5 years ago
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    Does my last answer make sense to you?

  18. anonymous
    • 5 years ago
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    umm...they intersect maximum number of times?... no

  19. anonymous
    • 5 years ago
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    What is an intersection?!

  20. anonymous
    • 5 years ago
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    cross.. meet at a point

  21. anonymous
    • 5 years ago
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    if you have circle 1 with the same radius as circle 2. And you draw circle with the same center as circle 2. Then they will have infinitely many intersection points; they actually intersect for all points in the two circles.

  22. anonymous
    • 5 years ago
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    ok yes... that makes sense

  23. anonymous
    • 5 years ago
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    That's only valid if they have the same radius.

  24. anonymous
    • 5 years ago
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    If they are with different radii, then they will not intersect at all when they have the same center.

  25. anonymous
    • 5 years ago
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    How are you figuring this out? Are these rules of circles?

  26. anonymous
    • 5 years ago
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    Not really, just think about it. It's very clear.

  27. anonymous
    • 5 years ago
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    ok so these are same radius different centers... how would I poistion 100 circles?

  28. anonymous
    • 5 years ago
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    oh the question says they have to have different centers?!

  29. anonymous
    • 5 years ago
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    Is this going to be a picture answer or a formula answer?..... yeah same radius different centers.... but the question just says how would you position 100 circles to intersect the maximum number of times.

  30. anonymous
    • 5 years ago
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    It was an a., b., c. type question. so I am not sure if it even pertains

  31. anonymous
    • 5 years ago
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    I think the max will be if all of them intersect at the center of some other circle.

  32. anonymous
    • 5 years ago
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    I would roughly say that each circuit has to intersect the others at two points.

  33. anonymous
    • 5 years ago
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    each one of the other circuits at two points*

  34. anonymous
    • 5 years ago
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    Is the question asking about the number of maximum intersection points?

  35. anonymous
    • 5 years ago
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    no just how to position 100 circles to intersect the maximum number of times

  36. anonymous
    • 5 years ago
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    Ok, as I say in a position such that each circuit would intersect twice with each one of the 99 remaining circuits.

  37. anonymous
    • 5 years ago
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    I am not sure of that answers the question.

  38. anonymous
    • 5 years ago
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    ok... I understand that....

  39. anonymous
    • 5 years ago
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    What do you think polpak?

  40. anonymous
    • 5 years ago
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    One sec

  41. anonymous
    • 5 years ago
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    Take your time!

  42. anonymous
    • 5 years ago
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    number of total points of intersection of n congruent circles = 2C(n, 2) 100 circles intersect in 2C(100, 2) = 400 points Does this look wack?

  43. anonymous
    • 5 years ago
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    100 times 2 = 200 a circles intersects twice... ???

  44. anonymous
    • 5 years ago
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    i hax a question

  45. anonymous
    • 5 years ago
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    Ok, so I think for positioning them you just have to arrange their centers around some point at intervals of \(2\pi/100\) radians a distance less than r from that point (where r is the radius of each circle).

  46. anonymous
    • 5 years ago
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    that will space them evenly at any rate.

  47. anonymous
    • 5 years ago
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    i haz a question, can you answer it plzzz????

  48. anonymous
    • 5 years ago
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    while still having each circle intersecting each other circle twice.

  49. anonymous
    • 5 years ago
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    Oh wow... so would that formula be the answer or plug in the numbers

  50. anonymous
    • 5 years ago
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    Thank you

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