## anonymous 5 years ago When a chunk of matal is dropped into a container of water the water level rises 3.4cm. The container is shaped like a cylinder with a radius of 3cm. What is the volume of the metal. Show work please<33

1. anonymous

pi r^2 h

2. anonymous

Volume of cylinder = (Area of the Base)*(Height) The base of a cylinder is a circle so, Area of a circle = (pi)r^2 The initial Height is X, after the metal is dropped it turns to x+3.4

3. anonymous

soo how would you find the volume of that metal? or the inital height?

4. anonymous

it is same as volue of water risen in container

5. anonymous

how would you find that out?

6. anonymous

$V' = \pi (3^{3})h = 9{\pi}h$$V'' = \pi(3^{3})(h+3) = 9h{\pi}+27{\pi}$ $V'' - V' = Vmetal$$9h{\pi}+27{\pi} - 9{\pi}h = 27{\pi}$

7. anonymous

Where V' = original volume V'' = after metal volume

8. anonymous

oh okay, but on the first equation for the after metal volume shouldnt it be (h+3.4)? or no..

9. anonymous

yea, you're right. instead of 27 it's 30.6

10. anonymous

so its 30.6pi?

11. anonymous

indeed

12. anonymous

Thanks so much I've got it now<3

13. anonymous

np