anonymous
  • anonymous
When a chunk of matal is dropped into a container of water the water level rises 3.4cm. The container is shaped like a cylinder with a radius of 3cm. What is the volume of the metal. Show work please<33
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
pi r^2 h
anonymous
  • anonymous
Volume of cylinder = (Area of the Base)*(Height) The base of a cylinder is a circle so, Area of a circle = (pi)r^2 The initial Height is X, after the metal is dropped it turns to x+3.4
anonymous
  • anonymous
soo how would you find the volume of that metal? or the inital height?

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anonymous
  • anonymous
it is same as volue of water risen in container
anonymous
  • anonymous
how would you find that out?
anonymous
  • anonymous
\[V' = \pi (3^{3})h = 9{\pi}h\]\[V'' = \pi(3^{3})(h+3) = 9h{\pi}+27{\pi}\] \[V'' - V' = Vmetal\]\[9h{\pi}+27{\pi} - 9{\pi}h = 27{\pi}\]
anonymous
  • anonymous
Where V' = original volume V'' = after metal volume
anonymous
  • anonymous
oh okay, but on the first equation for the after metal volume shouldnt it be (h+3.4)? or no..
anonymous
  • anonymous
yea, you're right. instead of 27 it's 30.6
anonymous
  • anonymous
so its 30.6pi?
anonymous
  • anonymous
indeed
anonymous
  • anonymous
Thanks so much I've got it now<3
anonymous
  • anonymous
np

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