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anonymous

  • 5 years ago

When a chunk of matal is dropped into a container of water the water level rises 3.4cm. The container is shaped like a cylinder with a radius of 3cm. What is the volume of the metal. Show work please<33

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  1. anonymous
    • 5 years ago
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    pi r^2 h

  2. anonymous
    • 5 years ago
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    Volume of cylinder = (Area of the Base)*(Height) The base of a cylinder is a circle so, Area of a circle = (pi)r^2 The initial Height is X, after the metal is dropped it turns to x+3.4

  3. anonymous
    • 5 years ago
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    soo how would you find the volume of that metal? or the inital height?

  4. anonymous
    • 5 years ago
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    it is same as volue of water risen in container

  5. anonymous
    • 5 years ago
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    how would you find that out?

  6. anonymous
    • 5 years ago
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    \[V' = \pi (3^{3})h = 9{\pi}h\]\[V'' = \pi(3^{3})(h+3) = 9h{\pi}+27{\pi}\] \[V'' - V' = Vmetal\]\[9h{\pi}+27{\pi} - 9{\pi}h = 27{\pi}\]

  7. anonymous
    • 5 years ago
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    Where V' = original volume V'' = after metal volume

  8. anonymous
    • 5 years ago
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    oh okay, but on the first equation for the after metal volume shouldnt it be (h+3.4)? or no..

  9. anonymous
    • 5 years ago
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    yea, you're right. instead of 27 it's 30.6

  10. anonymous
    • 5 years ago
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    so its 30.6pi?

  11. anonymous
    • 5 years ago
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    indeed

  12. anonymous
    • 5 years ago
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    Thanks so much I've got it now<3

  13. anonymous
    • 5 years ago
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    np

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