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toxicsugar22

  • 5 years ago

Delbert prepares a 25% glugose solution of by mixing 2 ml of glucose with 8 ml of water. If he adds x ml of glucose to the solution, its concentration is given by C(X)=2+x/8+x toxicsugar22: How many ml of glucose should delberrt add to increase the concentration to 50%

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  1. anonymous
    • 5 years ago
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    first find how much glucose it has by setting C(x)=.25\[.25 = {(2+x) \over (8+x)}\] find how much glucose does a 50% concentration solution has by setting the equation equal to 50%:\[.50 = {(2+x) \over (8+x)}\] Last, subtract the 50% x from the 25% x and you will have how much is need to add. is that right?

  2. toxicsugar22
    • 5 years ago
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    yes

  3. toxicsugar22
    • 5 years ago
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    thamks

  4. anonymous
    • 5 years ago
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    np

  5. toxicsugar22
    • 5 years ago
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    can u help me with on more

  6. anonymous
    • 5 years ago
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    sure, put it up

  7. toxicsugar22
    • 5 years ago
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    The cost in thousands of dollers for extracting p% of a precious ore from a mine is given by the equation C(p)=360p/100-p Complete this showing the cost of extracting various percents of the ore . if 15 is P then what is C

  8. toxicsugar22
    • 5 years ago
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    do u get it

  9. anonymous
    • 5 years ago
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    don't yu just substitu 15 for P in the C(p) equation?

  10. toxicsugar22
    • 5 years ago
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    not in the 360p/100-p

  11. toxicsugar22
    • 5 years ago
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    ok so how do i do that

  12. anonymous
    • 5 years ago
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    what is 15 ? p=15% ?

  13. toxicsugar22
    • 5 years ago
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    yes

  14. toxicsugar22
    • 5 years ago
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    so how do i do that can u show me please

  15. anonymous
    • 5 years ago
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    the we know that p =0.15 right?

  16. anonymous
    • 5 years ago
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    if we know that the cost is: C(p)=360p/100-p what would it be if p = 0.15? C(0.15) = ?

  17. toxicsugar22
    • 5 years ago
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    yes can u show me this one time

  18. anonymous
    • 5 years ago
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    C(0.15) = 360(0.15)/100-0.15

  19. toxicsugar22
    • 5 years ago
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    yes but it said do not convert percents to decimals

  20. toxicsugar22
    • 5 years ago
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    ok i got it

  21. anonymous
    • 5 years ago
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    sorry didn't see that 15/100 then

  22. toxicsugar22
    • 5 years ago
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    ok i got it

  23. toxicsugar22
    • 5 years ago
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    with that question what percent of the ore can be extracted if 540,000 can be spent on the extraction?

  24. anonymous
    • 5 years ago
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    now you set C(p) = 540,000 so, 540,000 = 360p/100-p solve for p

  25. toxicsugar22
    • 5 years ago
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    can u show me pleae

  26. anonymous
    • 5 years ago
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    540000(100-p) = 360p 54,000,000 - 540,000p = 360p 54,000,000 = 540,360p p = 99.93

  27. toxicsugar22
    • 5 years ago
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    thanks

  28. anonymous
    • 5 years ago
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    np

  29. toxicsugar22
    • 5 years ago
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    A computer store sells approximately 300 of its most popular model per year. The manager would like to minimize her annual inventory cost by ordering the optimal numbers of computers, x, at regular intervals. If she orders x computers in each shipment, the cost of storage willl be 6x dollers, and the cost of reording will be 300/x (15x+10) dollers. The inventory cost is the sum of the storage cost and the reording cost. use the distributive law to simplfy the expression for the rerding cost. Then express the inventory cost C as a function of x

  30. toxicsugar22
    • 5 years ago
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    can u help me

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