Delbert prepares a 25% glugose solution of by mixing 2 ml of glucose with 8 ml of water. If he adds x ml of glucose to the solution, its concentration is given by C(X)=2+x/8+x toxicsugar22: How many ml of glucose should delberrt add to increase the concentration to 50%

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Delbert prepares a 25% glugose solution of by mixing 2 ml of glucose with 8 ml of water. If he adds x ml of glucose to the solution, its concentration is given by C(X)=2+x/8+x toxicsugar22: How many ml of glucose should delberrt add to increase the concentration to 50%

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first find how much glucose it has by setting C(x)=.25\[.25 = {(2+x) \over (8+x)}\] find how much glucose does a 50% concentration solution has by setting the equation equal to 50%:\[.50 = {(2+x) \over (8+x)}\] Last, subtract the 50% x from the 25% x and you will have how much is need to add. is that right?
yes
thamks

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np
can u help me with on more
sure, put it up
The cost in thousands of dollers for extracting p% of a precious ore from a mine is given by the equation C(p)=360p/100-p Complete this showing the cost of extracting various percents of the ore . if 15 is P then what is C
do u get it
don't yu just substitu 15 for P in the C(p) equation?
not in the 360p/100-p
ok so how do i do that
what is 15 ? p=15% ?
yes
so how do i do that can u show me please
the we know that p =0.15 right?
if we know that the cost is: C(p)=360p/100-p what would it be if p = 0.15? C(0.15) = ?
yes can u show me this one time
C(0.15) = 360(0.15)/100-0.15
yes but it said do not convert percents to decimals
ok i got it
sorry didn't see that 15/100 then
ok i got it
with that question what percent of the ore can be extracted if 540,000 can be spent on the extraction?
now you set C(p) = 540,000 so, 540,000 = 360p/100-p solve for p
can u show me pleae
540000(100-p) = 360p 54,000,000 - 540,000p = 360p 54,000,000 = 540,360p p = 99.93
thanks
np
A computer store sells approximately 300 of its most popular model per year. The manager would like to minimize her annual inventory cost by ordering the optimal numbers of computers, x, at regular intervals. If she orders x computers in each shipment, the cost of storage willl be 6x dollers, and the cost of reording will be 300/x (15x+10) dollers. The inventory cost is the sum of the storage cost and the reording cost. use the distributive law to simplfy the expression for the rerding cost. Then express the inventory cost C as a function of x
can u help me

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