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anonymous
 5 years ago
prove the identity
(1+tan2x)/ (sin2x+cos2x)=sec2x
anonymous
 5 years ago
prove the identity (1+tan2x)/ (sin2x+cos2x)=sec2x

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myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0is it (tanx)^2 or tan(2x)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0ok i think its tan(2x)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0ok tan(2x)=sin(2x)/cos(2x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This question came up already, check for spanishkb31

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the identity works if the 2s are ^2

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0multiply both top and bottom by cos(2x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sin^2(x) + cos^2(x) = 1

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0so we have [cos(2x)+sin(2x)]/[cos(2x){sin(2x)+cos(2x)}]=1/cos(2x)=sec(2x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0...leaving 1+tan^2(x) = sec^2(x) which is an identity, but can be further proved by multiplying through by cos^2(x): sin^2(x) + cos^2(x) = 1

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0it doesnt have to be the "squareys"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Haha this is a coincidence. It works in both cases; if 2 is the exponent or part of the angle.
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