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anonymous
 5 years ago
(x+2)^1/4 + 2=5
anonymous
 5 years ago
(x+2)^1/4 + 2=5

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can you work that out? I got 607 by subtracting 2 and then ^4 on both sides.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(x+2)^(1/4)+2 = 5 Subtract 2 from both sides: (x+2)^(1/4) = 3 Let x+2 = r (cos(theta)+i sin(theta)) and write 3 in phasor form: (r (cos(theta)+i sin(theta)))^(1/4) = 3 (cos(0)+i sin(0)) Use de Moivre's theorem: r^(1/4) (cos(theta/4)+i sin(theta/4)) = 3 (cos(0)+i sin(0)) Equating moduli and arguments gives: r^(1/4) = 3 and theta/4 = 2 pi k Solving these equations and selecting the 1 distinct solutions gives: r = 81 and theta_1 = 0 Then the equation (x+2)^(1/4) = 3 has the solutions: x+2 = 81 Subtract 2 from both sides: x = 79 Now test that this solution is appropriate by substitution into the original equation: Check the solution x = 79: (x+2)^(1/4)+2 => 2+(2+79)^(1/4) = 5 So the solution is correct. Thus, the solution is: x = 79

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But if you could write it in terms that someone in intermediate algebra could understand that would also help, haha. Thanks nonetheless.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Never mind, I got it.
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