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anonymous

  • 5 years ago

find the derivative of the equation. h(z) = e[(−z^2)/2]

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  1. anonymous
    • 5 years ago
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    did you mean e ^ [(−z^2)/2] or e * [(−z^2)/2] ??

  2. anonymous
    • 5 years ago
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    the ^ not *... it's e raised to (-z^2)/2

  3. anonymous
    • 5 years ago
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    i got to be \[-xe^{{-x^{2} \over 2}} \]

  4. anonymous
    • 5 years ago
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    i think you're definitely right - that makes so much sense.. i forgot that the integration of e^x equals itself

  5. anonymous
    • 5 years ago
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    thanks for all your help - are you on here often??

  6. anonymous
    • 5 years ago
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    haha np. Yea, i'm on summer break now so i'll be here sometimes

  7. anonymous
    • 5 years ago
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    awesome - i'm working on problems for my calc 2 final.. so frustrating!

  8. anonymous
    • 5 years ago
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    oh boy.... calc SUCKS!!! lol btw you can give the people that help you medals, become their fan and bunch other stuff... pretty cool web site to get some help hehe

  9. anonymous
    • 5 years ago
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    haha tell me about it!! this final is our only grade in the class..how do i give medals? i'll totally give you a bunch!!

  10. anonymous
    • 5 years ago
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    haha that's even worse. There's a gray bar on every post, on this bar there's a button [give meal] just click on it. Also if you leave your mouse cursor on top of my nickname image, you see my fans lmao THanks

  11. anonymous
    • 5 years ago
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    i can't find it :-(.. i'll try to figure it out i'll be back asking questions later and the next few days.. btw just became a fan! haha thanks!

  12. anonymous
    • 5 years ago
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    hahaha alright, thanks. Good luck

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spraguer (Moderator)
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