## anonymous 5 years ago find the derivative of the equation. h(z) = e[(−z^2)/2]

1. anonymous

did you mean e ^ [(−z^2)/2] or e * [(−z^2)/2] ??

2. anonymous

the ^ not *... it's e raised to (-z^2)/2

3. anonymous

i got to be $-xe^{{-x^{2} \over 2}}$

4. anonymous

i think you're definitely right - that makes so much sense.. i forgot that the integration of e^x equals itself

5. anonymous

thanks for all your help - are you on here often??

6. anonymous

haha np. Yea, i'm on summer break now so i'll be here sometimes

7. anonymous

awesome - i'm working on problems for my calc 2 final.. so frustrating!

8. anonymous

oh boy.... calc SUCKS!!! lol btw you can give the people that help you medals, become their fan and bunch other stuff... pretty cool web site to get some help hehe

9. anonymous

haha tell me about it!! this final is our only grade in the class..how do i give medals? i'll totally give you a bunch!!

10. anonymous

haha that's even worse. There's a gray bar on every post, on this bar there's a button [give meal] just click on it. Also if you leave your mouse cursor on top of my nickname image, you see my fans lmao THanks

11. anonymous

i can't find it :-(.. i'll try to figure it out i'll be back asking questions later and the next few days.. btw just became a fan! haha thanks!

12. anonymous

hahaha alright, thanks. Good luck

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