2-3i / 5-i Would I multiply both by the denominator and then FOIL?

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2-3i / 5-i Would I multiply both by the denominator and then FOIL?

Mathematics
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would you like to write this in standard form?
if so multiply the bottom and the top by the bottom's conjugate
the conjugate of a+b is a-b the conjugate of a-b is a+b so what is the conjugate of 5-i?

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Other answers:

i+5?
right
So multiple top and bottom by i+5 and then foil?
(2-3i)(5+i) is the top --------- (5-i)(5+i) is the bottom now lets multiply
2*5+2i-15i-3i^2 is the top ________________ 5^2-i^2 is the bottom but what is i^2?
-1
right! so we have 10-13i-3(-1) _____________ 25-(-1) 10-13i+3 _________ 25+1 13-13i ______ 26
1-i ____ 2
25i isn't 25(-1)? making -25.
right 25i isn't 25(-1) but 25i^2 is 25(-1)=-25 but where did you get 25i or 25i^2
Oooooh, no I get what you mean now. The denominator was 25-i^2. So the final answer was/is 13-13i ------ 26 which simplified to: 1-i/2 ?
13/26-13i/26 1/2-i/2 because 26 and 13 are both divisible by 13
Right, so 1-i --- 2 ? Sorry if I'm beating the dead horse here.
Thank you so much.

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