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anonymous

  • 5 years ago

2-3i / 5-i Would I multiply both by the denominator and then FOIL?

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  1. myininaya
    • 5 years ago
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    would you like to write this in standard form?

  2. myininaya
    • 5 years ago
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    if so multiply the bottom and the top by the bottom's conjugate

  3. myininaya
    • 5 years ago
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    the conjugate of a+b is a-b the conjugate of a-b is a+b so what is the conjugate of 5-i?

  4. anonymous
    • 5 years ago
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    i+5?

  5. myininaya
    • 5 years ago
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    right

  6. anonymous
    • 5 years ago
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    So multiple top and bottom by i+5 and then foil?

  7. myininaya
    • 5 years ago
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    (2-3i)(5+i) is the top --------- (5-i)(5+i) is the bottom now lets multiply

  8. myininaya
    • 5 years ago
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    2*5+2i-15i-3i^2 is the top ________________ 5^2-i^2 is the bottom but what is i^2?

  9. anonymous
    • 5 years ago
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    -1

  10. myininaya
    • 5 years ago
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    right! so we have 10-13i-3(-1) _____________ 25-(-1) 10-13i+3 _________ 25+1 13-13i ______ 26

  11. myininaya
    • 5 years ago
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    1-i ____ 2

  12. anonymous
    • 5 years ago
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    25i isn't 25(-1)? making -25.

  13. myininaya
    • 5 years ago
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    right 25i isn't 25(-1) but 25i^2 is 25(-1)=-25 but where did you get 25i or 25i^2

  14. anonymous
    • 5 years ago
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    Oooooh, no I get what you mean now. The denominator was 25-i^2. So the final answer was/is 13-13i ------ 26 which simplified to: 1-i/2 ?

  15. myininaya
    • 5 years ago
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    13/26-13i/26 1/2-i/2 because 26 and 13 are both divisible by 13

  16. anonymous
    • 5 years ago
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    Right, so 1-i --- 2 ? Sorry if I'm beating the dead horse here.

  17. anonymous
    • 5 years ago
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    Thank you so much.

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