anonymous
  • anonymous
find the first derivative of y=1-cos2x + 2cos^2x.
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
you have to use chain rule with the cos: \[\cos(ax) dx= asin(ax) \]
anonymous
  • anonymous
ok, thank you!
anonymous
  • anonymous
np

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dumbcow
  • dumbcow
just a note: d/dx cos(x) = -sin(x) so above there should be a neg sign in front of asin(ax)
anonymous
  • anonymous
ops, confused with integrals hehe. Thanks cow
anonymous
  • anonymous
\[y=1 - \text{Cos}[2*x] + 2*\text{Cos}[x]^2 = 2 \] Derivative of 2 is zero.

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