## anonymous 5 years ago i need some help in solving (1/c+3)+(c^2-3/c^2-9)+(1/3-c) please. the right answer's 1, but i don't seem to understand how to get it. :(

1. dumbcow

does this equal anything or are you just simplifying?

2. anonymous

just simplifying. thank you. :)

3. dumbcow

c^2 -9 can be factored to (c+3)(c-3) (3-c) a neg sign can be factored out --> -(c-3) common denominator is (c+3)(c-3) combined fraction should look like this: $\frac{(c-3) + (c ^{2}-3) -(c+3)}{(c+3)(c-3)}$ add like terms on top $\frac{c ^{2}-9}{(c+3)(c-3)}$ FOIL the bottom and then it cancels leaving 1.

4. anonymous

thank you! no wonder, i got mixed up with the negative signs!