anonymous
  • anonymous
Light falls on a photoelectric surface that has a work function of 2.90 eV. If the voltage required to stop the ejected electrons is 0.210 V, what is the wavelength of the incident radiation?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[\theta=hf\] is the formula to solve this problem
anonymous
  • anonymous
since work function is 2.90eV, nd Stopping Potential is0.210eV, so energy incident=Work function+ Max kinetic Energy(Stopping Potential), \[h \nu=\phi+Kmax\] Therefore .\[h \nu=\]2.9eV+0.21eV =3.11eV=\[hc/\lambda\], calculate \[\lambda\]=\[hc\3.11\times1.6\times10^{-19}\]=399.48nm (by calculation)

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