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anonymous

  • 5 years ago

what is the first partial dervative of f(x,y)=x^y to the respect of y

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  1. myininaya
    • 5 years ago
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    treat x like a contstant what is the derivative of f(y)=3^y lnf(y)=ln3^y lnf(y)=yln3 f'(y)/f(y)=ln3 f'(y)=ln3*f(y) f'(y)=ln3*3^y so if we have f(x,y)=x^y, then f_y=lnx*x^y

  2. myininaya
    • 5 years ago
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    brb i have to brush my teeth

  3. anonymous
    • 5 years ago
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    lnf(y)=yln3,f'(y)/f(y)=ln3 how this step is pertformed?

  4. myininaya
    • 5 years ago
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    i took derivative of both sides

  5. myininaya
    • 5 years ago
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    what is the derivative of f(x)=ln(x^2-1)

  6. myininaya
    • 5 years ago
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    f'(x)=(x^2-1)'/(x^2-1)=2x/(x^2-1)

  7. anonymous
    • 5 years ago
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    that sounds about right. i am going to try it out

  8. myininaya
    • 5 years ago
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    yay fun

  9. anonymous
    • 5 years ago
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    thank you

  10. myininaya
    • 5 years ago
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    great! i'm glad it worked out for you

  11. myininaya
    • 5 years ago
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    who gave me that medal? thanks whoever lol

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