anonymous
  • anonymous
A circle is defined by the following equation: -2x^(2)-2y^(2)+24x-54=0 What are the coordinates ofits center?
Mathematics
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anonymous
  • anonymous
A circle is defined by the following equation: -2x^(2)-2y^(2)+24x-54=0 What are the coordinates ofits center?
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
(6,0)
anonymous
  • anonymous
HEY CHIZZ whats d ans
anonymous
  • anonymous
^what?

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anonymous
  • anonymous
first rewrite the equations as \[2x^2+2y^2-24x-54=0\] divide by 2 \[x^2+y^2-12x-27=0\] complete the square: \[(x-6)^2+y^2=27=36=63\] center is (6,0) radius is \[\sqrt{63}\]
anonymous
  • anonymous
typo. 27+36 = 63
anonymous
  • anonymous
another mistake. should be +54 not -54 so right hand side is -27+ 36 = 9 and radius is 3. sorry
anonymous
  • anonymous
so is the center still (6,0)?

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