anonymous 5 years ago A circle is defined by the following equation: 3x^(2)+3y^(2)-24x+42y+183=0 What is its radius?

1. anonymous

i get $\sqrt{126}$

2. anonymous

let me try it slowly. $3x^3+3y^3-24x+42y=-183$ $x^2-8x + y^2 +14y=-61$ $(x-4)^2+(y-7)^2=-61+16+49=4$ radius is 2

3. anonymous

should be $(x-4)^2+(y+7)^2=4$ doesn't matter for radius, but center is (4,-7) not (4,7) hope the steps are clear: make the coefficient of the square terms 1 and then complete the square.

4. anonymous

where did you get the cubes from?