## anonymous 5 years ago can some one check this

1. anonymous

$f(x)=x^2+5x+1$put into the differance quo =2x+5+h

2. anonymous

yes. $\frac{f(x+h)-f(x)}{h}=\frac{(x+h)^2+5(x+h)+1-(x^2+5x+1)}{h}$ $\frac{x^2+2xh+h^2+5x+5h+1-x^2-5x-1}{h}$ $\frac{2xh+5h+h^2}{h}$ $2x+5+h$