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anonymous

  • 5 years ago

In solving the equation (x + 4)(x – 7) = -24, Eric stated that the solution would be x + 4 = -24 => x = -28 or (x – 7) = -24 => x = -17 However, at least one of these solutions fails to work when substituted back into the original equation. Why is that? Please help Eric to understand better; solve the problem yourself, and explain your reasoning.

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  1. anonymous
    • 5 years ago
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    this sound like it was written by a math teacher. if the product of two numbers is -24 you have no idea what the two numbers are. one is z, the other is \[\frac{-24}{z}\] if you want to solve this quadratic, you must multiply out and collect terms, set = 0 and solve.

  2. radar
    • 5 years ago
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    Yep, Eric messed up, he did not solve the problem.

  3. anonymous
    • 5 years ago
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    \[(x+4)(x-7)=-24\] \[x^2-3x-28=-24\] \[x^2-3x-52=0\] etc

  4. anonymous
    • 5 years ago
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    that is wrong it would be x^2 -3x -4=0

  5. anonymous
    • 5 years ago
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    yes you are right and i am wrong makes it much easier

  6. anonymous
    • 5 years ago
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    lol satellite \[x^2 - 3x - 28 = -24\] \[x^2 - 3x -4 = 0\]

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spraguer (Moderator)
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