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anonymous
 5 years ago
In solving the equation (x + 4)(x – 7) = 24, Eric stated that the solution would be
x + 4 = 24 => x = 28
or
(x – 7) = 24 => x = 17
However, at least one of these solutions fails to work when substituted back into the original equation. Why is that? Please help Eric to understand better; solve the problem yourself, and explain your reasoning.
anonymous
 5 years ago
In solving the equation (x + 4)(x – 7) = 24, Eric stated that the solution would be x + 4 = 24 => x = 28 or (x – 7) = 24 => x = 17 However, at least one of these solutions fails to work when substituted back into the original equation. Why is that? Please help Eric to understand better; solve the problem yourself, and explain your reasoning.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this sound like it was written by a math teacher. if the product of two numbers is 24 you have no idea what the two numbers are. one is z, the other is \[\frac{24}{z}\] if you want to solve this quadratic, you must multiply out and collect terms, set = 0 and solve.

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Yep, Eric messed up, he did not solve the problem.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[(x+4)(x7)=24\] \[x^23x28=24\] \[x^23x52=0\] etc

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that is wrong it would be x^2 3x 4=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes you are right and i am wrong makes it much easier

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol satellite \[x^2  3x  28 = 24\] \[x^2  3x 4 = 0\]
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