anonymous
  • anonymous
Use the discriminant to determine whether the following equations have solutions that are: two different rational solutions; two different irrational solutions; exactly one rational solution; or two different imaginary solutions. x2 = -4x – 4
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
im not sure hahaha... sorry ._."
radar
  • radar
The discriminant is the value of\[b ^{2}-4ac\] Do you know what the values of a, b, c are?
anonymous
  • anonymous
no sorry. never done a problem like this before

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

radar
  • radar
well a is the coefficient of the x^2 b is the coefficient of x c is the numerical constant your equation is:\[x ^{2}=-4x-4\]
anonymous
  • anonymous
ok.
radar
  • radar
I am going to rearrange the equation so that appears.\[x ^{2}+4x+4=0\] I added 4x+4 to both sides. This is legal as I did it to both sides of the equal sign. Do you follow that?
anonymous
  • anonymous
yes
radar
  • radar
a=1 b=4 c=4
radar
  • radar
discriminant is \[1^{2}-(-4)(1)(4)=1+16=17\]
anonymous
  • anonymous
ok. proceed
radar
  • radar
Now the important partl. If discriminant is positive, there are two real solutions. If ther discriminant is 0, there is one repeated solution. If the discriminant is negative there are no real solutions. Which category did the discriminant for your equation fit ?
radar
  • radar
Hold on a minute, i messed up\[4^{2}-4(1)(4)=16-16=0\]
anonymous
  • anonymous
ther are two real solutions
radar
  • radar
That was before I corrected the values for the discriminant which now equals 0
radar
  • radar
There is one repeated solution. the equation can be factored (x+2)(x+2)=0 x=-2 x=-2 see one repeated solution.
radar
  • radar
Sorry about the error, but it was noted before closing this thread. good luck in your studies.
anonymous
  • anonymous
geekgirl1988, what grade are you in? So that we can help accordingly

Looking for something else?

Not the answer you are looking for? Search for more explanations.