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anonymous
 5 years ago
Use the discriminant to determine whether the following equations have solutions that are: two different rational solutions; two different irrational solutions; exactly one rational solution; or two different imaginary solutions.
x2 = 4x – 4
anonymous
 5 years ago
Use the discriminant to determine whether the following equations have solutions that are: two different rational solutions; two different irrational solutions; exactly one rational solution; or two different imaginary solutions. x2 = 4x – 4

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im not sure hahaha... sorry ._."

radar
 5 years ago
Best ResponseYou've already chosen the best response.0The discriminant is the value of\[b ^{2}4ac\] Do you know what the values of a, b, c are?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no sorry. never done a problem like this before

radar
 5 years ago
Best ResponseYou've already chosen the best response.0well a is the coefficient of the x^2 b is the coefficient of x c is the numerical constant your equation is:\[x ^{2}=4x4\]

radar
 5 years ago
Best ResponseYou've already chosen the best response.0I am going to rearrange the equation so that appears.\[x ^{2}+4x+4=0\] I added 4x+4 to both sides. This is legal as I did it to both sides of the equal sign. Do you follow that?

radar
 5 years ago
Best ResponseYou've already chosen the best response.0discriminant is \[1^{2}(4)(1)(4)=1+16=17\]

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Now the important partl. If discriminant is positive, there are two real solutions. If ther discriminant is 0, there is one repeated solution. If the discriminant is negative there are no real solutions. Which category did the discriminant for your equation fit ?

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Hold on a minute, i messed up\[4^{2}4(1)(4)=1616=0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ther are two real solutions

radar
 5 years ago
Best ResponseYou've already chosen the best response.0That was before I corrected the values for the discriminant which now equals 0

radar
 5 years ago
Best ResponseYou've already chosen the best response.0There is one repeated solution. the equation can be factored (x+2)(x+2)=0 x=2 x=2 see one repeated solution.

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry about the error, but it was noted before closing this thread. good luck in your studies.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0geekgirl1988, what grade are you in? So that we can help accordingly
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