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anonymous

  • 5 years ago

Use the discriminant to determine whether the following equations have solutions that are: two different rational solutions; two different irrational solutions; exactly one rational solution; or two different imaginary solutions. x2 = -4x – 4

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  1. anonymous
    • 5 years ago
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    im not sure hahaha... sorry ._."

  2. radar
    • 5 years ago
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    The discriminant is the value of\[b ^{2}-4ac\] Do you know what the values of a, b, c are?

  3. anonymous
    • 5 years ago
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    no sorry. never done a problem like this before

  4. radar
    • 5 years ago
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    well a is the coefficient of the x^2 b is the coefficient of x c is the numerical constant your equation is:\[x ^{2}=-4x-4\]

  5. anonymous
    • 5 years ago
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    ok.

  6. radar
    • 5 years ago
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    I am going to rearrange the equation so that appears.\[x ^{2}+4x+4=0\] I added 4x+4 to both sides. This is legal as I did it to both sides of the equal sign. Do you follow that?

  7. anonymous
    • 5 years ago
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    yes

  8. radar
    • 5 years ago
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    a=1 b=4 c=4

  9. radar
    • 5 years ago
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    discriminant is \[1^{2}-(-4)(1)(4)=1+16=17\]

  10. anonymous
    • 5 years ago
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    ok. proceed

  11. radar
    • 5 years ago
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    Now the important partl. If discriminant is positive, there are two real solutions. If ther discriminant is 0, there is one repeated solution. If the discriminant is negative there are no real solutions. Which category did the discriminant for your equation fit ?

  12. radar
    • 5 years ago
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    Hold on a minute, i messed up\[4^{2}-4(1)(4)=16-16=0\]

  13. anonymous
    • 5 years ago
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    ther are two real solutions

  14. radar
    • 5 years ago
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    That was before I corrected the values for the discriminant which now equals 0

  15. radar
    • 5 years ago
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    There is one repeated solution. the equation can be factored (x+2)(x+2)=0 x=-2 x=-2 see one repeated solution.

  16. radar
    • 5 years ago
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    Sorry about the error, but it was noted before closing this thread. good luck in your studies.

  17. anonymous
    • 5 years ago
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    geekgirl1988, what grade are you in? So that we can help accordingly

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