Find the specified nth term in the expansion of the binomial. (Write the expansion in descending powers of x.) (x + 5y)^10, n = 4 A. 210x^6y^4 B. 15,000x^7y^3 C. 210x^6y^4 D. 9,765,625y^10 E. 5040x^6y^4

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Find the specified nth term in the expansion of the binomial. (Write the expansion in descending powers of x.) (x + 5y)^10, n = 4 A. 210x^6y^4 B. 15,000x^7y^3 C. 210x^6y^4 D. 9,765,625y^10 E. 5040x^6y^4

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n=10? I believe??? \
nevermind... term in the expansion
which is a different variable rth term of expansion

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I guess I understand how to write it all out just not how to simplify it correctly to get a condensed answer like the ones they provide
http://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut54_bi_theor.htm Look at example 8... if you have problems I'll do it out for you
pascals triangle
Ha ha I'm on that site right now trying to work it out lol Does it matter though if it's rth term or nth term?
doesn't matter coz thats just a variable
1 1,1 1,2,1 1,3,3,1 1,4,6,4,1 1,5,10,10,5,1 1,6,15,20,15,6,1 1,7,21,35,35,21,7,1 1,8,28,56,70,56,28,8,1 1,9,36,84,126,126,84,36,9,1 1,10,45,120,210, ....
well if you are following the site, the rth term is 4, the nth term is 10
120 (x^7) (y^3)
answer is b though
120 (x^7) ((5y)^3)
120.125 x^7 y^3 15000 x^7 y^3
BBBBBBBBBB
\[{10 \choose 4 }=210\] 4th term is \[210 x^6 (5y)^4\]
of course i could be wrong. the 'n=4' is not clear.
lol..... im prolly wrong :)
wow ok the answer I got isn't even close to any of these.... I got 100800x^7125y^3....not quite sure what id id wrong
the 4th term is 120 x^7 y^3 as a standard... tehn you have to account for the coeefs in the original problem....namely the +5 attached to the y
120 x^7 (5y)^3
120.125 x^7 y^3 15000 x^7 y^3 :)
oh ok makes sense ok Can I try another one on my own and have you check it?
sure; but you can check it with pascals triangle; i posted that first to like half the 10th spot ;)
ok :)
ok the problem is: Find the specified nth term in the expansion of the binomial. (Write the expansion in descending powers of x.) (x - 2y)^12, n = 6 I got 760x^7y^5 which is definitly not one of my answer choices....
at 6 eh 12 11 10 9 8 7 x^6 y^6 is gonne be the variable answers
you got any with ony an x^6 y^6 as an asnswer?
oh it's cause I used the 12 instead of the six let me try it again....
ack..you were right with the x and y lol...i lost count :)
x^7 y^5 is the 6th term
oh ok so I was right now....idk how I got the 760.... cause that's nowhere close to their choices
lol..... which choice has the right x and y parts?
narrow it down if its multiple choice ;)
- 25,344, but that just doesn't seem right to me oh well I guess
well lets play detective shall we :) is the - part correct? -2^5 = a negative right? so i believe the negative is right... if its got the right x and y parts, then its a sure shot
ok well thank you very much!
Do you know the binomial theorem?! It's quite easy to do it using this theorem.
learning it I think i just have to keep practicing using cause I get numbers mixed up and stuff
I see.
ya it's weird I can find the x and y parts but the number before I somehow lkeep messing up

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