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anonymous

  • 5 years ago

expresss complex number in rectangular form \[\sqrt{7}*cis*2.1 \]

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  1. anonymous
    • 5 years ago
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    is that cosine ?

  2. anonymous
    • 5 years ago
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    its cis cos+isin

  3. anonymous
    • 5 years ago
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    yes it is stupid notation for \[cos(\theta)+i sin(\theta)\]

  4. anonymous
    • 5 years ago
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    im trying square of 7 which is 2.64 times cos but cos(?)

  5. anonymous
    • 5 years ago
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    i also assume that you are working in radians, not degrees. So just use a calculator. \[\sqrt{7} [cos(2.1)+i sin(2.1)]\]

  6. anonymous
    • 5 years ago
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    i get -1.336 for a and 2.284 for b (rounded) so answer is -1.336 + 2.284 i

  7. amistre64
    • 5 years ago
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    the cosine part relates to the x coord; the i sin part relates to the y coord right?

  8. amistre64
    • 5 years ago
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    Did the others parse it tight to be: cos(2.1) + i sin(2.1)?

  9. amistre64
    • 5 years ago
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    (-1.34, 42.30) is what i get with radian measurements...

  10. amistre64
    • 5 years ago
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    2.28.. musta hit a wrong buttononthe calc :)

  11. anonymous
    • 5 years ago
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    yes cosine is x and sine is y, usually written as a and b as in a + bi. I doubt it is (-1.34,42.3) for two reasons: the rectangular form of a complex number is a number, not a coordinate. so it should look like a + bi also we know that the absolute value of that number is \[\sqrt7\]

  12. amistre64
    • 5 years ago
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    correct, its similar to polar coordinates in that respect. But i think the exercise here is to see that complex numbers are nothing new and that they can be plotted in the same manner as rectangular coords...right?

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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