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anonymous

  • 5 years ago

i need help figuring out how to work this problem. the width of a rectangle is 6 in less than the lengh. the perimeter is 120 in. find the dimensions

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  1. anonymous
    • 5 years ago
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    let the length be x

  2. anonymous
    • 5 years ago
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    then the width is x-6 the perimeter is 2(leng + breadth) = 120 2 (x + x-6) = 120 2x-6 = 60 x=33

  3. anonymous
    • 5 years ago
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    ok ty so much

  4. anonymous
    • 5 years ago
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    2x+2y = 12 or x+y=60 x=y-6 y + y-6=60 2y=66 y=33 x=27

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