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anonymous

  • 5 years ago

49b^2+41b+9 Solve showing step by step please

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  1. amistre64
    • 5 years ago
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    what do you get when you try it?

  2. amistre64
    • 5 years ago
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    the most basic method would be to complete the square; which is just the long hand version of the quadratic formula

  3. anonymous
    • 5 years ago
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    \[49b^2+41b+9\] \[ax^2+bx+c=0\] quadratic formula:\[roots = {-b \pm \sqrt{\Delta} \over 2a} \] where,\[\Delta = b^2-4ac\]

  4. amistre64
    • 5 years ago
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    isnt writing delta for a shortcut, and then haveing to define delta kinda defeating the purpose of writing delta to begin with ;)

  5. anonymous
    • 5 years ago
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    That's an expression and not an equation

  6. anonymous
    • 5 years ago
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    well, it depends.. you can use Delta to find the vertex so... you never know, always good to have as a side (:

  7. amistre64
    • 5 years ago
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    how do you use delta, the discriminate, to find the vertex?

  8. anonymous
    • 5 years ago
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    After you find Delta, discriminate the points of vertex should be: y=-D/4a at x=-b/2a

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