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anonymous
 5 years ago
find the difference quotient
f(x) = 4 +3xx^2
f(3+h)  f(3)/h
please show work
anonymous
 5 years ago
find the difference quotient f(x) = 4 +3xx^2 f(3+h)  f(3)/h please show work

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the whole thing is over h

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1substitute (3+h) and (3) into your function then divide by h and use algebraic techniques to solve

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you end up with 3  2x

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1if you simply want someone to go thru the effort of typing it all out for you so that you can copy it to your homework; im sure someone will oblige ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0not true, I am taking a class and I just don't understand how to do some of the problems. I am a single mom going back to school and struggling a bit. Thanks for your help.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1then at what part does your understanding begin to fade?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1im a single dad going back to college.... so that really doesnt apply does it?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1suppose we have the function: f(x) = x+2 How do we determine: f(5) ??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Good for you apparently you are better off then I am. I am just looking for help ok?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1or simply put: f(x=5) ?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1thats right :) then for these that you have we do that same, but with the x=3 and the x=3+h

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1what do those look like then?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so I will end up with 2 answers?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1youll end up subtracting one function from the other ...yes, 4 +3xx^2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.14 +3(3+h)(3+h)^2  [4 +3(x)(3)^2] = ?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1when all that tedious window dressing is done; you should obtain the result; 3+h2x for an answer :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do i multiply by h then to get rid of the h on the bottom?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you can simply divide everything by h to get rid of it; since there is no = sign to equate to, we should avoid doing the multiply by 'h'.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1it might be correct, but i dont know how accurate it can be :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.14 + 9 + 3h 9 6h h^2  4 9 + 81  is what i get so far, if i didnt mess it up h

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1gonna have to work it on paper; i get to many typos this way :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1see, 3^2 = 9; not 81 :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The following expression replaces the x in the function value by (h+3) subtract the result of replacing the x in the function value by 3 and then dividing this result by h. \[\left(4+3 xx^2\text{/.}x\to h+3\right)\frac{\left(4+3 xx^2\text{/.}x\to 3\right)}{h} \]= \[9+3 (3+h)(3+h)^23 x \] Although I could be wrong.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.14 + 9 + 3h 9 6h h^2  4 9 + 9  h 3h h^2 3h h^2  =    = 3 h ... but i gotta recheck myself again :) h h h

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.132x; as x> 3 we get 3 6 = 3; ...its good :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1as h> 0 we get 3 as an answer, right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1now how can i make this clearer? or are we good with it?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1robtob; good effort, wrong interpretation of the expression ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0amistre64, Blundered on the first post. I think the following is now correct. At 76 years if age I cannot type with the toes of my left foot and monitor what is going on on the computer screen in real time. \[\left(4+3 xx^2\text{/.}x\to h+3\right)\frac{\left(4+3 xx^2\text{/.}x\to 3\right)}{h}=4\frac{4}{h}3 hh^2 \]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[\frac{[4 + 3(3+h)  (3+h)^2]  [4+3(3)(3)^2]}{h}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1since the original equation is : 4+3xx^2...it has to derive down to: 3 2x; and at f(3) that has to equal 3 when h=0

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[\frac{[4+994+99] 3h  h^2}{h}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[\frac{3h}{h}  \frac{h^2}{h}\] equals: 3  h

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1when h = 0; this is 3 :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you so much for your help, sorry my internet dropped

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1'sok; internets a fickle beast :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0amistre64, googled: difference quotient and looked at the first hit. http://answers.yahoo.com/question/index?qid=20090320184937AAl0VC6 Got the general idea now. Thanks.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I hope i am not in over my head going back to school and starting with a calc class. This site has been really helpful.
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