anonymous
  • anonymous
find the difference quotient f(x) = 4 +3x-x^2 f(3+h) - f(3)/h please show work
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
the whole thing is over h
amistre64
  • amistre64
substitute (3+h) and (3) into your function then divide by h and use algebraic techniques to solve
amistre64
  • amistre64
you end up with 3 - 2x

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amistre64
  • amistre64
if you simply want someone to go thru the effort of typing it all out for you so that you can copy it to your homework; im sure someone will oblige ;)
anonymous
  • anonymous
not true, I am taking a class and I just don't understand how to do some of the problems. I am a single mom going back to school and struggling a bit. Thanks for your help.
amistre64
  • amistre64
then at what part does your understanding begin to fade?
amistre64
  • amistre64
im a single dad going back to college.... so that really doesnt apply does it?
amistre64
  • amistre64
suppose we have the function: f(x) = x+2 How do we determine: f(5) ??
anonymous
  • anonymous
Good for you apparently you are better off then I am. I am just looking for help ok?
amistre64
  • amistre64
or simply put: f(x=5) ?
anonymous
  • anonymous
You put 5 in for x
amistre64
  • amistre64
thats right :) then for these that you have we do that same, but with the x=3 and the x=3+h
amistre64
  • amistre64
what do those look like then?
anonymous
  • anonymous
so I will end up with 2 answers?
amistre64
  • amistre64
youll end up subtracting one function from the other ...yes, 4 +3x-x^2
amistre64
  • amistre64
4 +3(3+h)-(3+h)^2 - [4 +3(x)-(3)^2] = ?
anonymous
  • anonymous
ok I understand now
amistre64
  • amistre64
when all that tedious window dressing is done; you should obtain the result; 3+h-2x for an answer :)
anonymous
  • anonymous
do i multiply by h then to get rid of the h on the bottom?
amistre64
  • amistre64
you can simply divide everything by h to get rid of it; since there is no = sign to equate to, we should avoid doing the multiply by 'h'.
amistre64
  • amistre64
it might be correct, but i dont know how accurate it can be :)
anonymous
  • anonymous
ok
amistre64
  • amistre64
4 + 9 + 3h -9 -6h -h^2 - 4 -9 + 81 ------------------------------- is what i get so far, if i didnt mess it up h
amistre64
  • amistre64
gonna have to work it on paper; i get to many typos this way :)
amistre64
  • amistre64
see, 3^2 = 9; not 81 :)
anonymous
  • anonymous
The following expression replaces the x in the function value by (h+3) subtract the result of replacing the x in the function value by 3 and then dividing this result by h. \[\left(4+3 x-x^2\text{/.}x\to h+3\right)-\frac{\left(4+3 x-x^2\text{/.}x\to 3\right)}{h} \]= \[9+3 (3+h)-(3+h)^2-3 x \] Although I could be wrong.
amistre64
  • amistre64
4 + 9 + 3h -9 -6h -h^2 - 4 -9 + 9 ------------------------------- h -3h -h^2 -3h h^2 -------- = ---- - ---- = -3 -h ... but i gotta recheck myself again :) h h h
amistre64
  • amistre64
3-2x; as x-> 3 we get 3 -6 = -3; ...its good :)
amistre64
  • amistre64
as h-> 0 we get -3 as an answer, right?
amistre64
  • amistre64
now how can i make this clearer? or are we good with it?
amistre64
  • amistre64
robtob; good effort, wrong interpretation of the expression ;)
anonymous
  • anonymous
amistre64, Blundered on the first post. I think the following is now correct. At 76 years if age I cannot type with the toes of my left foot and monitor what is going on on the computer screen in real time. \[\left(4+3 x-x^2\text{/.}x\to h+3\right)-\frac{\left(4+3 x-x^2\text{/.}x\to 3\right)}{h}=4-\frac{4}{h}-3 h-h^2 \]
amistre64
  • amistre64
:)
amistre64
  • amistre64
\[\frac{[4 + 3(3+h) - (3+h)^2] - [4+3(3)-(3)^2]}{h}\]
amistre64
  • amistre64
since the original equation is : 4+3x-x^2...it has to derive down to: 3 -2x; and at f(3) that has to equal -3 when h=0
amistre64
  • amistre64
\[\frac{[4+9-9-4+9-9] -3h - h^2}{h}\]
amistre64
  • amistre64
\[\frac{-3h}{h} - \frac{h^2}{h}\] equals: -3 - h
amistre64
  • amistre64
when h = 0; this is -3 :)
anonymous
  • anonymous
thank you so much for your help, sorry my internet dropped
amistre64
  • amistre64
'sok; internets a fickle beast :)
anonymous
  • anonymous
amistre64, googled: difference quotient and looked at the first hit. http://answers.yahoo.com/question/index?qid=20090320184937AAl0VC6 Got the general idea now. Thanks.
anonymous
  • anonymous
I hope i am not in over my head going back to school and starting with a calc class. This site has been really helpful.

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