anonymous
  • anonymous
4+2/x / x/3+1/6 can someone help me solve this please
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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amistre64
  • amistre64
\[\frac{\frac{4+2}{x}}{\frac{x}{3}+\frac{1}{6}}\]this thing?
anonymous
  • anonymous
is there and "=" sign or is this a compound fraction?
amistre64
  • amistre64
solve might mean simplify ;) just my assumption tho

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anonymous
  • anonymous
\[4 + 2/x \div x/3 + 1/6\]
anonymous
  • anonymous
in that case multiply top and bottom by 6x to clear fractions. or if you want you can do the subtraction in the denominator, and then divide by multiplying by the reciprocal of the denominator (after you subtract).
amistre64
  • amistre64
multiply everything by 6x could work
anonymous
  • anonymous
ooooh \[4+\frac{2}{x} \div \frac{x}{3} + \frac{1}{6}\] ?
anonymous
  • anonymous
yes that
mathmagician
  • mathmagician
12/x
anonymous
  • anonymous
can you tell me how you got the answer please
anonymous
  • anonymous
\[4+\frac{2}{x} \times \frac{3}{x} + \frac{1}{6}=4+ \frac{1}{6}+\frac{6}{x^2}=\frac{25}{6}+\frac{6}{x^2}\]
amistre64
  • amistre64
24x+12 12(2x+1) ------- = -------- = 4 if i did it right :) 6x +3 3(2x+1)
mathmagician
  • mathmagician
\[4+2/x=(4x+2)/x and x/3+1/6=(2x+1)/6. Then 4x+2/6 multiplied by 6/(2x+1) is equal \to 12/x\]
anonymous
  • anonymous
sorry i did not realize it was \[\frac{\frac{x+2}{x}}{\frac{x}{3}+\frac{1}{6}}\]
amistre64
  • amistre64
but i see an error in mine :) 6x(x/3) = 2x^2
amistre64
  • amistre64
24x +12 -------- perhaps? 2x^2 +x
anonymous
  • anonymous
it it perhaps \[\frac{4+\frac{2}{x}}{\frac{x}{3}+\frac{1}{6}}\]?
amistre64
  • amistre64
\[\frac{4x+2}{x}*\frac{6}{2x+1}\]
amistre64
  • amistre64
12/x

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