## anonymous 5 years ago someone please tell me what i am doing wrong multiply and simplify z² 8z+24 ----- *--------- 9z+27 8z^9

1. M

need to show your work first

2. anonymous

factor out a (z+3) in the numerator and denominator, leaving 8/9 cancel z^2 and leave z^7 in denominator

3. amistre64

simplify everything to factors to see what you can cross out

4. anonymous

z^2(8z+24)=z^2*8(z+3) (9z+27)(8z^9)=8(z+3)*8*z^9 8z^2(z+3) 8z^2(z+3) * 1/8z^9 1*1/8z^9 1/8z^9

5. amistre64

is that sposed to be an equals sign between them?

6. anonymous

yes this is the equation z² * 8z+24 9z+27 8z^9

7. amistre64

$\frac{z z}{9 (z+3)} * \frac{8(z+3)}{8zzzzzzzzz}$

8. amistre64

get rid of 2 z's top and bottom; and the (z+3) top and bottom to get; and the 8's top to bottom to get: 1/9z^6

9. amistre64

ack!!... 1/9z^7 :) forgot how to subtract

10. amistre64

does that make sense?

11. anonymous

i think so will u show the work so i can make notes for the next problem

12. amistre64

i did show the work.... cant really see how to show any more of it :/

13. anonymous

in my work i think i forgot about the 9

14. amistre64

when everything is factored; you simple cancel out (its a bad term really) everything that is the same top to bottom; because they go to 1 z/z = 1 8/8 = 1 (z+3)/(z+3) = 1 so they become redundant in the equation

15. amistre64

whats left is: 1 ------ 9 z^7

16. anonymous

ty that makes more sense