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anonymous

  • 5 years ago

someone please tell me what i am doing wrong multiply and simplify z² 8z+24 ----- *--------- 9z+27 8z^9

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  1. M
    • 5 years ago
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    need to show your work first

  2. anonymous
    • 5 years ago
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    factor out a (z+3) in the numerator and denominator, leaving 8/9 cancel z^2 and leave z^7 in denominator

  3. amistre64
    • 5 years ago
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    simplify everything to factors to see what you can cross out

  4. anonymous
    • 5 years ago
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    z^2(8z+24)=z^2*8(z+3) (9z+27)(8z^9)=8(z+3)*8*z^9 8z^2(z+3) 8z^2(z+3) * 1/8z^9 1*1/8z^9 1/8z^9

  5. amistre64
    • 5 years ago
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    is that sposed to be an equals sign between them?

  6. anonymous
    • 5 years ago
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    yes this is the equation z² * 8z+24 9z+27 8z^9

  7. amistre64
    • 5 years ago
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    \[\frac{z z}{9 (z+3)} * \frac{8(z+3)}{8zzzzzzzzz}\]

  8. amistre64
    • 5 years ago
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    get rid of 2 z's top and bottom; and the (z+3) top and bottom to get; and the 8's top to bottom to get: 1/9z^6

  9. amistre64
    • 5 years ago
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    ack!!... 1/9z^7 :) forgot how to subtract

  10. amistre64
    • 5 years ago
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    does that make sense?

  11. anonymous
    • 5 years ago
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    i think so will u show the work so i can make notes for the next problem

  12. amistre64
    • 5 years ago
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    i did show the work.... cant really see how to show any more of it :/

  13. anonymous
    • 5 years ago
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    in my work i think i forgot about the 9

  14. amistre64
    • 5 years ago
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    when everything is factored; you simple cancel out (its a bad term really) everything that is the same top to bottom; because they go to 1 z/z = 1 8/8 = 1 (z+3)/(z+3) = 1 so they become redundant in the equation

  15. amistre64
    • 5 years ago
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    whats left is: 1 ------ 9 z^7

  16. anonymous
    • 5 years ago
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    ty that makes more sense

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