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anonymous

  • 5 years ago

douald has investments totaling 4,000 in two accounts-one a savings account paying 3% interest and the other bond paying 5%. if the annual from the two investment was 180%, how much did he have in invested at each rate?

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  1. anonymous
    • 5 years ago
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    douald has investments totaling 4,000 in two accounts-one a savings account paying 3% interest and the other bond paying 5%. if the annual from the two investment was 180, how much did he have in invested at each rate?

  2. anonymous
    • 5 years ago
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    Let funds deposited into account 1 be A and funds deposited into account 2 be B. A + B = 4000, since the total amount invested is $4,000. Since A earns interest at 3% and B earns interest at 5%, we can set up a second equation like this: A*.03 + B*.05 = 180

  3. anonymous
    • 5 years ago
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    ok

  4. anonymous
    • 5 years ago
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    So you have A+B=4000 And .03A + .05B=180 Can you solve one of those for A or B? The first one, maybe?

  5. anonymous
    • 5 years ago
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    no can u show me how

  6. anonymous
    • 5 years ago
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    Let's solve for A by subtracting B from both sides: A+B=4000 - B -------------- A =4000-B

  7. anonymous
    • 5 years ago
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    Now you can substitute that in for A in the second equation: .03(4000-B) + .05B = 180

  8. anonymous
    • 5 years ago
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    i thought i subtract the like terms

  9. anonymous
    • 5 years ago
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    I'm not sure what you mean.

  10. anonymous
    • 5 years ago
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    o while ill do it your way

  11. anonymous
    • 5 years ago
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    ok wat i do now

  12. anonymous
    • 5 years ago
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    Distribute .03: .03*4000 - .03B + .05B = 180

  13. anonymous
    • 5 years ago
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    ok i did it

  14. anonymous
    • 5 years ago
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    Okay, what did you get? Then simplify it.

  15. anonymous
    • 5 years ago
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    is the answer 120.02

  16. anonymous
    • 5 years ago
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    Well, .03*4000 = 120.00. But that is not the answer to the problem. We need to solve for A and B.

  17. anonymous
    • 5 years ago
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    ok is u workin it out to

  18. anonymous
    • 5 years ago
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    I want you to understand how to get there, I'd rather not just give you the answer.

  19. anonymous
    • 5 years ago
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    When you distribute .03: .03*4000 -.03B +.05B what do you get?

  20. anonymous
    • 5 years ago
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    i know hw answer i just said was the wronge answer

  21. anonymous
    • 5 years ago
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    .03*4000 -.03B+.05B = 120 + .02B = 180 Subtract 120 from both sides .02B=60 Divide 60/.02=B=3000 Plug back in to the original equation A+3000=4000 Therefore A = 1000 and B = 3000

  22. anonymous
    • 5 years ago
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    want it be -0.35b=60

  23. anonymous
    • 5 years ago
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    then wat do i do next

  24. anonymous
    • 5 years ago
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    I worked it all out above.

  25. anonymous
    • 5 years ago
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    how much did he have invested at each rate?

  26. anonymous
    • 5 years ago
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    I already answered the question. .03*4000 -.03B+.05B = 120 + .02B = 180 Subtract 120 from both sides .02B=60 Divide 60/.02=B=3000 Plug back in to the original equation A+3000=4000 Therefore A = 1000 and B = 3000

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