anonymous
  • anonymous
find an expression for the area under the graph of f as limit ( do not evaluate de limits) f(x)=1+x^4 2<=x<=5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
integrate wrt to x using limits of 2 and 5
anonymous
  • anonymous
can u show step by step
anonymous
  • anonymous
ok, first, you integrate 1, which becomes X.

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anonymous
  • anonymous
then, you integrate x^4 using the power rule
anonymous
  • anonymous
can you do that?
anonymous
  • anonymous
x+x5/5
anonymous
  • anonymous
x+x^5/5
anonymous
  • anonymous
noo,, wait.. im doing antidivative,, i dont know
anonymous
  • anonymous
no, you got it. Ok. So, evaluate at the upper bound, 5, and then the lower bound, 2. then subtract the upper bound from the lower bound.
anonymous
  • anonymous
ok let me try
anonymous
  • anonymous
reverse what I said, you need to subtract the lower bound from the upper bound.
anonymous
  • anonymous
3
anonymous
  • anonymous
i havent evaluated it yet, lemme try
anonymous
  • anonymous
wait... i subtract the lower from upper 5-2 =3
anonymous
  • anonymous
:(
anonymous
  • anonymous
no, you have an integrated expression which needs to be evaluated... So, X+x^5/5----plug in 5 for x then plug in 2 for x and subtract your answers
anonymous
  • anonymous
ohhhh
anonymous
  • anonymous
i have the answer figured, and I'll check yours for you when you get it.
anonymous
  • anonymous
583
anonymous
  • anonymous
?
anonymous
  • anonymous
um, not what I got.
anonymous
  • anonymous
i pluged 2 in 2+2^5/5 5+5^5/5
anonymous
  • anonymous
so 2+32/5=42
anonymous
  • anonymous
evaluated at your upper bound you should have 630. Your lower bound should be 42/5. Subtracting the two should give you 621.6.
anonymous
  • anonymous
2+32/5=42/5
anonymous
  • anonymous
yeaa
anonymous
  • anonymous
=D you got tripped up on the arithmetic. But you know how to integrate, and that's important.
anonymous
  • anonymous
jajajaajjaja
anonymous
  • anonymous
627-8.4=618.6
anonymous
  • anonymous
??
anonymous
  • anonymous
:)
anonymous
  • anonymous
upper bound should be 630.
anonymous
  • anonymous
630-8.4=Correct
anonymous
  • anonymous
wow,,, no that bad in aritmetic lol
anonymous
  • anonymous
calculator..:) ok what shoul i do after?
anonymous
  • anonymous
thats it hot rod. Done. You just figured out the area under a curve.
anonymous
  • anonymous
noww need to estimate de distance using L and R
anonymous
  • anonymous
? huh?
anonymous
  • anonymous
wait.. i have to checp to here i am ok
anonymous
  • anonymous
oh, crap wait.... you weren't supposed to evaluate at the limits were you?

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