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integrate wrt to x using limits of 2 and 5
can u show step by step
ok, first, you integrate 1, which becomes X.
then, you integrate x^4 using the power rule
can you do that?
noo,, wait.. im doing antidivative,, i dont know
no, you got it. Ok. So, evaluate at the upper bound, 5, and then the lower bound, 2. then subtract the upper bound from the lower bound.
ok let me try
reverse what I said, you need to subtract the lower bound from the upper bound.
i havent evaluated it yet, lemme try
wait... i subtract the lower from upper 5-2 =3
no, you have an integrated expression which needs to be evaluated... So, X+x^5/5----plug in 5 for x then plug in 2 for x and subtract your answers
i have the answer figured, and I'll check yours for you when you get it.
um, not what I got.
i pluged 2 in 2+2^5/5 5+5^5/5
evaluated at your upper bound you should have 630. Your lower bound should be 42/5. Subtracting the two should give you 621.6.
=D you got tripped up on the arithmetic. But you know how to integrate, and that's important.
upper bound should be 630.
wow,,, no that bad in aritmetic lol
calculator..:) ok what shoul i do after?
thats it hot rod. Done. You just figured out the area under a curve.
noww need to estimate de distance using L and R
wait.. i have to checp to here i am ok
oh, crap wait.... you weren't supposed to evaluate at the limits were you?